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Greeley [361]
3 years ago
13

What structural features help us identify a compound as an alkane, a cycloalkane, an alkene, an alkyne, a saturated hydrocarbon

or an aromatic hydrocarbon?
1. _______ contains at least one ring of three or more carbon atoms joined by single bonds.
2._________ contains at least one double bond between carbon atoms.
3. _________ is an acryclic hydrocarbon that contains only single bonds.
4.__________ contains one or more planar, six membered rings of carbon atoms with delocalized pi-bonding throughout the ring
5. _____ contains only single bonds.
6.______ contains at least one triple bond between carbon atoms.
Chemistry
1 answer:
elena55 [62]3 years ago
5 0
1. Cycloalkane
2. Alkene
3. Saturated Hydrocarbon
4. Aromatic Hydrocarbon
5. Alkane
6. Alkyne
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Lelechka [254]

Answer:

216/84 Po + 4/2 He a

Explanation:

6 0
2 years ago
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How many kJ of heat are released by the reaction of 25.0 g of Na2O2(s) in the following reaction? (M = 78.0 g/mol for Na2O2)
solong [7]

-20.16 KJ of heat are released by the reaction of 25.0 g of Na2O2.

Explanation:

Given:

mass of Na2O2 = 25 grams

atomic mass of Na2O2 = 78 gram/mole

number of mole = \frac{mass}{atomic mass of 1 mole}

                          = \frac{25}{78}

                          =0. 32 moles

The balanced equation for the reaction:

2 Na2O2(s) + 2 H2O(l) → 4 NaOH(aq) + O2(g) ∆Hο = −126 kJ

It can be seen that 126 KJ of energy is released when 2 moles of Na2O2 undergoes reaction.

similarly 0.3 moles of Na2O2 on reaction would give:

\frac{126}{2} = \frac{x}{0.32}

x = \frac{126 x 0.32}{2}

 = -20.16 KJ

Thus, - 20.16 KJ of energy will be released.

6 0
3 years ago
The hypothetical elements shown here (figures a–d) do not include hydrogen or helium. Which element would you expect to bond cov
Marizza181 [45]
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3 years ago
Deposition can occur where wind or running water slows down? true or false
Shalnov [3]

Answer:

The answer is True.

Explanation:

6 0
3 years ago
The decomposition of NI3 to form N2 and I2 releases −290.0 kJ of energy. The reaction can be represented as 2NI3(s)→N2(g)+3I2(g)
EastWind [94]

Answer:

-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.

Explanation:

Mass of nitrogen triiodide = 20.0 g

Moles of nitrogen triiodide = \frac{20.0 g}{395 g/mol}=0.05063 mol

2NI_3(s)\rightarrow N_2(g)+3I_2(g), \Delta H_{rxn}=-290.0 kJ

According to reaction, 2 moles of nitrogen triiodide gives 290.0 kilo Joules of heat on decomposition ,then 0.05063 moles of nitrogen triiodide will give :

\frac{-290.0 kJ}{2}\times 0.05063=-7.34 kJ

-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.

3 0
3 years ago
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