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den301095 [7]
3 years ago
12

Suppose that the equilibrium tuition at College X is $2,000 a semester and the tuition that students are charged is $1,000 a sem

ester. At $1,000 tuition a semester,
Chemistry
1 answer:
Vinvika [58]3 years ago
4 0

Answer:

a. quantity demanded of openings at the college is greater than quantity supplied.

Explanation:

Here is the full question :

Suppose that the equilibrium tuition at College X is $2,000 a semester and the tuition that students are charged is $1,000 a semester. At $1,000 tuition a semester,

a.quantity demanded of openings at the college is greater than quantity supplied.

b.quantity supplied of openings at the college is greater than quantity demanded.

c.quantity supplied of openings at the college equals quantity demanded.

d.quantity supplied of openings equals demand.

e.none of the above

Equilibrium price is the price at which quantity demanded equals quantity supplied.

When price is below equilibrium price, quantity demanded would exceed quantity supplied. As a result there would be scarcity. Prices would rise until equilibrium is reached

When price is above equilibrium price, quantity supplied would exceed quantity demanded, As a result, there would be surplus. Prices would fall until equilibrium is reached

Equilibrium tuition is $2,000 but the tuition charged is $1000. Thus, there would be excess demand over supply

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Answer: Initial pH is 13.243

12.83

1.3

40ml

7

Explanation:

Just finished the test.

5 0
3 years ago
What type of bond is most likely being represented in row 1?
Angelina_Jolie [31]

ionic is the awnser have a blessed day

5 0
4 years ago
Read 2 more answers
How many g NaOH should be required to completely react 1.876 g of Copper (II) nitrate?
Doss [256]

\\ \tt\hookrightarrow 2NaOH+Cu(NO_3)_2\longrightarrow 2NaNO_3+Cu(OH)_2

Moles of copper nitrate:-

\\ \tt\hookrightarrow \dfrac{1.876}{187.56}=0.001mol

  • 1mol of Copper nitrate reacts with 2mol NaOH
  • 0.001mol will react with 0.002mol NaOH

Madd of NaOH

\\ \tt\hookrightarrow 0.002(40)=0.08g

8 0
2 years ago
_Li + __F2 → _LIF<br> How do I balance this?
Semmy [17]

Answer:

 2Li   +   F₂    →    2LiF

Explanation:

The reaction expression is given as:

          Li   +   F₂    →     LiF

We are to balance the expression. In that case, the number of atoms on both sides of the expression must be the same.

 Let use a mathematical approach to solve this problem;

  Assign variables a,b and c as the coefficients that will balance the expression:

             aLi   +  bF₂    →     cLiF

Conserving Li: a  = c

                   F:  2b  = c

          let a = 1, c  = 1 and b  = \frac{1}{2}  

  Multiply through by 2;

        a  = 2, b = 1 and c  = 2

               2Li   +   F₂    →    2LiF

 

5 0
3 years ago
There are eight consitutional isomers with the molecular formula C4H11N.
Dmitriy789 [7]

Answer:

See figure 1

Explanation:

We have to remember that in the isomer structures we have to <u>change the structure</u> but we have to maintain the <u>same formula</u>, in this case C_4H_1_1N.

In the formula, we have 1 nitrogen atom. Therefore we will have as a main functional group the <u>amine group</u>.

In the amines, we have different types of amines. Depending on the number of carbons bonded to the "N" atom. In the <em>primary amines</em>, we have only 1 C-H. In the <em>secondary amines</em>, we have two C-N bonds and in the <em>tertiary amines</em>, we have three C-N bonds.

With this in mind, we can have:

-) <u>Primary amines:</u>

1) n-butyl amine

2) sec-butyl amine including 2 optical isomers

3) isobutyl amine

4) tert-butyl amine

-) <u>Secondary amines:</u>

5) N-methyl n-propyl amine

6) N-methyl isopropyl amine

7) N, N-diethyl amine

-) <u>Tertiary amines:</u>

8) N-ethyl N, N-dimethyl amine

See figure 1

I hope it helps!

8 0
3 years ago
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