Answer:
A
Explanation:
A solution is homogeneous mixture composed of only one phase where a solute is dissolved into a solvent.
Main Answer: The standard electrode potential of galvanic cell constructed from barium and manganese electrode is 4.097.
Explanation:
When the galvanic cell constructed between Manganese and Barium, the half reactions will be as follows:
Mn2+(aq) + 2e-⟶ Mn(s) E1 = −1.185
Ba2+(aq) + 2e-⟶ Ba(s) E2 = −2.912
By considering the above two reactions, the standard electrode potential can be calculated.
The galvanic cell standard electrode potential is given by E1 + E2 = 1.185 + 2.912 = 4.097 volts
What is standard electrode potential?
Standard electrode potential is defined as the measure of reducing power of any compound or element. Its units are volts.
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To get the melting point of a solution so, we will use this formula:
ΔT = - mKf
when:
m is molality of the solution
Kf is cryoscopic constant of water = 1.86 C/m
and ΔT is the change in melting point (T2 - 0 °C)
so, now we need to calculate the molality to substitute:
when the molality = moles NaCl / Kg of water
and when moles NaCl = mass / molar mass
= 2.5 g / 58 g/mol
= 0.043 mol
∴ Kg water = volume *density /1000
= 230 mL * 1 g/mL / 1000
= 0.23 Kg
∴ molality = 0.043 / 0.23 =0.187 M
by substitution:
T2-0°C = - 0.187 * 1.86
∴T2 = - 0.348 °C
When water molecules align with each other, a weak bond is established between the negatively charged oxygen atom<span> of one water molecule and the positively charged </span>hydrogen atoms<span> of a neighboring water molecule. The weak bond that often forms between </span>hydrogen atoms<span> and neighboring atoms is the hydrogen bond.</span>
Answer:
moles Na = 0.1114 g / 22.9898 g/mol=0.004846
moles Tc = 0.4562g /98.9063 g/mol=0.004612
mass O = 0.8961 - ( 0.1114 + 0.4562)=03285 g
moles O = 0.3285 g/ 15.999 g/mol=0.02053
divide by the smallest
0.02053/ 0.004612 =4.45 => O
0.004846/ 0.004612 = 1.0 => Tc
to get whole numbers multiply by 2
Na2Tc2O 9
Explanation:
Hope it right hope it helps
