Answer:
We conclude that:
''add 3 and the sum of 9 and v'' is algebraically represented by the expression as:
Step-by-step explanation:
Given the statement
''add 3 and the sum of 9 and v''
Let us break down the statement
so
Adding 3 and the sum of 9 and v will be: 3 + 9 + v
Therefore, we conclude that:
''add 3 and the sum of 9 and v'' is algebraically represented by the expression as:
Answer:
11.7
Step-by-step explanation:
multiply RS by the scale factor to get R'S'
Answer:
The rectangle has a width of 4 and a height of 8
Step-by-step explanation:
Let the height of the rectangle be H and the width be W.
We know the height of the rectangle is twice the width, so:
H = 2W
The area of a rectangle, A, is given by A = W * H, so in this case:
32 = W * 2W
32 = 2W²
W² = 16
W = 4
Knowing that the width is 4, the height must be 8. This gives us an area of 32.
Answer:
The max. revenue is $57,121.
This happens with 239 passengers.
The price of the ticket is $239 per person.
Step-by-step explanation:
Let the variable "P" denote the number of passengers.
If P=180, then the ticket cost is $298/person. Then the price is reduced by $1 for each additional person.
In general, if P=(180+x), then the ticket cost becomes (298-x) per person.
The revenue can be defined as the ticket cost multplied by the number of passengers:

We can derive R and equal to zero to maximize the function.

The amount of passengers is:
The price of the tickets is

The revenue is:
Answer:
510g H2S
Step-by-step explanation:
En esta pregunta, se nos pide calcular la masa de H2S emitida cuando 5 moles de sulfuro de níquel reaccionan completamente con el agua.
De la ecuación equilibrada, podemos ver que 1 mol de sulfuro de níquel produjo 3 moles de sulfuro de hidrógeno Por lo tanto, 5 moles de sulfuro de níquel producirán = 5 * 3 moles = 15 moles de sulfuro de hidrógeno
Matemáticamente, la masa se puede calcular multiplicando el número de moles por masa molar La masa molar de H2S es 2 (1) + 32 = 34 g / mol La masa en gramos así producida = 15 mol * 34g / mol = 510g