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Andreyy89
3 years ago
9

Según la reacción de abajo, ?Cuantos gramos ácido sulfhídrico se desprenden, cuando reaccionan completamente 5 moles de sulfuro

niquélico? Los pesos atómicos son: Ni: 58.7 uma, S: 32 uma, O: 16 uma, H: 1 uma
Ni2S3 + 6 H2O ---> 2 Ni(OH)3 + 3 H2S
Mathematics
1 answer:
lisov135 [29]3 years ago
5 0

Answer:

510g H2S

Step-by-step explanation:

En esta pregunta, se nos pide calcular la masa de H2S emitida cuando 5 moles de sulfuro de níquel reaccionan completamente con el agua.

De la ecuación equilibrada, podemos ver que 1 mol de sulfuro de níquel produjo 3 moles de sulfuro de hidrógeno Por lo tanto, 5 moles de sulfuro de níquel producirán = 5 * 3 moles = 15 moles de sulfuro de hidrógeno

Matemáticamente, la masa se puede calcular multiplicando el número de moles por masa molar La masa molar de H2S es 2 (1) + 32 = 34 g / mol La masa en gramos así producida = 15 mol * 34g / mol = 510g

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