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Andreyy89
3 years ago
9

Según la reacción de abajo, ?Cuantos gramos ácido sulfhídrico se desprenden, cuando reaccionan completamente 5 moles de sulfuro

niquélico? Los pesos atómicos son: Ni: 58.7 uma, S: 32 uma, O: 16 uma, H: 1 uma
Ni2S3 + 6 H2O ---> 2 Ni(OH)3 + 3 H2S
Mathematics
1 answer:
lisov135 [29]3 years ago
5 0

Answer:

510g H2S

Step-by-step explanation:

En esta pregunta, se nos pide calcular la masa de H2S emitida cuando 5 moles de sulfuro de níquel reaccionan completamente con el agua.

De la ecuación equilibrada, podemos ver que 1 mol de sulfuro de níquel produjo 3 moles de sulfuro de hidrógeno Por lo tanto, 5 moles de sulfuro de níquel producirán = 5 * 3 moles = 15 moles de sulfuro de hidrógeno

Matemáticamente, la masa se puede calcular multiplicando el número de moles por masa molar La masa molar de H2S es 2 (1) + 32 = 34 g / mol La masa en gramos así producida = 15 mol * 34g / mol = 510g

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Evaluate sin 300° without using a calculator.
Anni [7]

Answer:

-\sqrt{3} /2

Step-by-step explanation:

300 degrees is in the fourth quadrant (it's between 270 and 360); sine is negative in the fourth quadrant.

Given we're in the fourth quadrant, the reference angle is 360 - 300 = 60 degrees

sin(60°) = \sqrt{3} /2

And since sine is negative, this value turns negative:

sin(300°) = -\sqrt{3} /2

3 0
2 years ago
Given circle P with arc AE=53, arc BA=68 and arc CB=72 match the following angles with their corresponding measurements
11Alexandr11 [23.1K]
From the diagram;
1. Angle 2 = ADB+BDH
                                           = arcAB/2 +90 
                                           = 34 +90 
                                           = 124°

2. Angle 4= 90°,
Reason ; the angle between a tangent and a radius is equal to 90. A tangent is a line that touches the circumference of a circle once even if prolonged.

3. Angle 5 = 90 -BDC (note the acr subtends twice the angle it subtends on the circumference to the center.
             = 90-arc BC/2
             = 90-36
              = 54°

4. Angle 6 = BFD
             = 180-ADB-FBD
             = 180-AB/2-DE/2
             But DE = 180 -121 = 59
Therefore, BFD = 180 -34-29.5
             = 116.5°

5. Angle 1 = 180- BFD (angles on a straight line add up to 180°)
              = 180- 116.5
              = 63.5°
           

6. Angle 3 = 180 -(ADB+BFD)
             = 180 -(34 +116.5)
             =  180- 150.5
             = 29.5°
similarly angle 3 = DE/2 = 59/2 = 29.5°

7. Angle 8= 90, because BD is diameter;
 angles subtended by a diameter to the circumference is always a right angle (90°)


8.Angle 7 =  BE
               but BE= AB+AE
                          = 68+ 53
                          = 121°
                 


    
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The graph of f(x)=3•2^x -3 is shown below. G(x) is a transformation of f(x). How would you write the equation for the function g
Bezzdna [24]

Answer:

C

Step-by-step explanation:

To find the appropriate equation, notice the red graph has shifted up about 6 units. This means that 3*2^x-3 which is shifted by -3 will move 6 up. -3+6= 3. This means the function will have +3. Only B and C are options. Now test a point. Notice the red function crosses the y-axis at about 5 or 6 when x=0.

g(x) = 2^x+3\\g(0) = 2^0+3\\g(0)=1+3\\g(0)=4

This function doesn't match.

f(0) = 3*2^0+3\\f(0) = 3*1+3\\f(0)=6

This function matches. Option C is correct.

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