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hjlf
2 years ago
5

Enter the chemical equation 2H+(aq)+S2−(aq)→H2S(g). Express your answer as a chemical equation.

Chemistry
2 answers:
Natasha_Volkova [10]2 years ago
6 0

Enter the chemical equation 2H+(aq)+S2−(aq)→H2S(g). Express your answer as a chemical equation: 2H^+ (aq) + S^{2-}(aq) => H_2S(g)

<h3 /><h3>Further explanation </h3>

The skill that must be know in chemistry is writing the chemical equations, because these equations are the representations of chemical reactions between substances. The chemical equation consists of substances reacting on the left side and the products formed on the right side, with a right arrow inserted to show a chemical reaction taking place. The phases of the substances are included by writing them as subscripts contained in a parenthesis.

For chemical reactions involving ions, the superscripts are used and the number is usually placed before the charge (i.e. 2+, not +2).

For the given chemical reaction, the complete chemical equation including the phases given by:

2H^+ (aq) + S^{2-}(aq) => H_2S(g)

Sulfur S  is a chemical element with the symbol S and atomic number 16. It is abundant, multivalent, and nonmetallic.  Whereas Hydrogen sulfide H_2S  is a colorless chalcogen hydride gas with the characteristic is very poisonous, corrosive, and flammable.  Hydrogen H   is the most abundant chemical substance in the Universe

<h3>Learn more</h3>
  1. Learn more about the chemical equation brainly.com/question/12271256
  2. Learn more about Hydrogen sulfide brainly.com/question/12592944
  3. Learn more about Sulfur brainly.com/question/4288925

<h3>Answer details</h3>

Grade:  9

Subject:  Chemistry

Chapter:  the chemical equation

Keywords: the chemical equation, Introduction to Mastering Chemistry, Chemistry, equation, Hydrogen sulfide

amm18122 years ago
4 0

Answer : The complete chemical equation is,

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

Explanation :

As we know that, in a chemical equation the reacting species present on left side and the product formed present on right side and a right arrow inserted between the reactants and product that show a chemical reaction taking place.

In the chemical reaction, the phases of the substances are also included and subscripts and superscripts are also used for the numbers.

For the given chemical reaction, the balanced chemical equation including the phases, is given by:

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

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Answer:

Pb₂O₄

                               

Explanation:

The given species are:

        Pb⁴⁺               O²⁻  

Now, to solve this problem, we use the combining powers which corresponds to the number of electrons usually lost or gained or shared by atoms during the course of a chemical combination.

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4 0
2 years ago
You have a solution of 600 mg of caffeine dissolved in 100 mL of water. The partition coefficient for aqueous caffeine extracted
klio [65]

Answer:

159 mg caffeine is being extracted in 60 mL dichloromethane

Explanation:

Given that:

mass of caffeine in 100 mL of water =  600 mg

Volume of the water = 100 mL

Partition co-efficient (K) = 4.6

mass of caffeine extracted = ??? (unknown)

The portion of the DCM = 60 mL

Partial co-efficient (K) = \frac{C_1}{C_2}

where; C_1= solubility of compound in the organic solvent and C_2 = solubility in aqueous water.

So; we can represent our data as:

K=(\frac{A_{(g)}}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL} )

Since one part of the portion is A and the other part is B

A+B = 60 mL

A+B = 0.60

A= 0.60 - B

4.6=(\frac{0.6-B(mg)}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL})

4.6 = \frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}

4.6 × (\frac{B_{(mg)}}{100mL}) = (\frac{0.6-B(mg)}{60mL} )

4.6 B *\frac{60}{100} = 0.6 - B

2.76 B = 0.6 - B

2.76 + B = 0.6

3.76 B = 0.6

B = \frac{0.6}{3.76}

B = 0.159 g

B = 159 mg

∴ 159 mg caffeine is being extracted from the 100 mL of water containing 600 mg of caffeine with one portion of in 60 mL dichloromethane.

4 0
3 years ago
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A sample of CO2 weighing 86.34g contains how many molecules?
irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

86.34 g CO₂

<u>Step 2: Identify Conversion</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

<u />86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.18141 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

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It is given as,

Ea (rev) = Ea (fwd) − ΔHrxn

Given,

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Ea (fwd) = 86 kJ/mol

Substituting the values above as:

Ea (rev) = 86 - 83

= 3 kJ

Therefore, the activation energy of the reverse reaction is 3 kJ.

Learn more about activation energy, here:

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