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hjlf
2 years ago
5

Enter the chemical equation 2H+(aq)+S2−(aq)→H2S(g). Express your answer as a chemical equation.

Chemistry
2 answers:
Natasha_Volkova [10]2 years ago
6 0

Enter the chemical equation 2H+(aq)+S2−(aq)→H2S(g). Express your answer as a chemical equation: 2H^+ (aq) + S^{2-}(aq) => H_2S(g)

<h3 /><h3>Further explanation </h3>

The skill that must be know in chemistry is writing the chemical equations, because these equations are the representations of chemical reactions between substances. The chemical equation consists of substances reacting on the left side and the products formed on the right side, with a right arrow inserted to show a chemical reaction taking place. The phases of the substances are included by writing them as subscripts contained in a parenthesis.

For chemical reactions involving ions, the superscripts are used and the number is usually placed before the charge (i.e. 2+, not +2).

For the given chemical reaction, the complete chemical equation including the phases given by:

2H^+ (aq) + S^{2-}(aq) => H_2S(g)

Sulfur S  is a chemical element with the symbol S and atomic number 16. It is abundant, multivalent, and nonmetallic.  Whereas Hydrogen sulfide H_2S  is a colorless chalcogen hydride gas with the characteristic is very poisonous, corrosive, and flammable.  Hydrogen H   is the most abundant chemical substance in the Universe

<h3>Learn more</h3>
  1. Learn more about the chemical equation brainly.com/question/12271256
  2. Learn more about Hydrogen sulfide brainly.com/question/12592944
  3. Learn more about Sulfur brainly.com/question/4288925

<h3>Answer details</h3>

Grade:  9

Subject:  Chemistry

Chapter:  the chemical equation

Keywords: the chemical equation, Introduction to Mastering Chemistry, Chemistry, equation, Hydrogen sulfide

amm18122 years ago
4 0

Answer : The complete chemical equation is,

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

Explanation :

As we know that, in a chemical equation the reacting species present on left side and the product formed present on right side and a right arrow inserted between the reactants and product that show a chemical reaction taking place.

In the chemical reaction, the phases of the substances are also included and subscripts and superscripts are also used for the numbers.

For the given chemical reaction, the balanced chemical equation including the phases, is given by:

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

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A frictionless piston cylinder device is subjected to 1.013 bar external pressure. The piston mass is 200 kg, it has an area of
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Answer:

a) T_{2} = 360.955\,K, P_{2} = 138569.171\,Pa\,(1.386\,bar), b) T_{2} =  347.348\,K, V_{2} = 0.14\,m^{3}

Explanation:

a) The ideal gas is experimenting an isocoric process and the following relationship is used:

\frac{T_{1}}{P_{1}} = \frac{T_{2}}{P_{2}}

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T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (30.1\,\frac{J}{mol\cdot K} )}

T_{2} = 360.955\,K

The final pressure is:

P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}

P_{2} = \frac{360.955\,K}{298\,K}\cdot \left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}}\right)

P_{2} = 138569.171\,Pa\,(1.386\,bar)

b) The ideal gas is experimenting an isobaric process and the following relationship is used:

\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}

Final temperature is cleared from this expression:

Q = n\cdot \bar c_{p}\cdot (T_{2}-T_{1})

T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{p}}

T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (38.4\,\frac{J}{mol\cdot K} )}

T_{2} =  347.348\,K

The final volume is:

V_{2} = \frac{T_{2}}{T_{1}}\cdot V_{1}

V_{2} = \frac{347.348\,K}{298\,K}\cdot (0.12\,m^{3})

V_{2} = 0.14\,m^{3}

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