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zaharov [31]
3 years ago
8

PLEASE HELP!!! DUE TOMORROW

Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0
Thermal energy measures the total kinetic energy of the particles in a substance. The greater the motion of particles, the higher a substance's temperature and thermal energy. A substance's total thermal energy depends on its temperature, number of atoms, and physical state.
You might be interested in
g is incident on 3 successive sheets of polarizing material. The transmission axis of the first sheet is vertical. The transmiss
murzikaleks [220]

Answer:

The intensity of light passing from the third polarizer is 3Io/16.

Explanation:

The law of Malus is given by

I=I_o cos^2\theta

Let the incident intensity of light is Io.

The intensity of light passing from the first polarizer is

I' = \frac{I_o}{2}

The intensity of light passing from the second polarizer is

I''=\frac{I_o}{2}\times cos^230 =\frac{3I_o}{8}

The intensity of light passing from the third polarizer is

I''' = \frac{3I_o}{8}\times cos^2 60\\\\\\I''' = \frac{3I_o}{16}

6 0
3 years ago
PLEASE HELP!!! DUE TOMORROW
Dmitry_Shevchenko [17]
Thermal energy measures the total kinetic energy of the particles in a substance. The greater the motion of particles, the higher a substance's temperature and thermal energy. A substance's total thermal energy depends on its temperature, number of atoms, and physical state.
6 0
3 years ago
How much force can a 2.5 kg sledge hammer excerpt on a nail if you can swing the hammer at 20 m/s and the hammer contacts the na
AleksAgata [21]

Answer:

625 N

Explanation:

The impulse given to the nail is equal to the change in momentum of the hammer:

I=F \Delta t=m \Delta v

where

F is the force exerted by the hammer

\Delta t=0.08 s is the time of contact

m=2.5 kg is the mass

\Delta v=20 m/s is the change in velocity of the hammer

Substituting the data and re-arranging the equation, we can find the force:

F=\frac{m \Delta v}{\Delta t}=\frac{(2.5 kg)(20 m/s)}{0.08 s}=625 N

4 0
4 years ago
A shopping cart is given an initial velocity of 4 m/s and experiences a constant acceleration of 4 m/s2. What is the magnitude o
NNADVOKAT [17]

Answer:

48m

Explanation:

  • Initial velocity = 4m/s
  • Acceleration = 4m/s²
  • Time = 4s
  • Displacement = ?

From Second equation of motion ,

\longrightarrow s = ut + 1/2at²

\longrightarrow s = 4*4 + 1/2*4*(4)² m

\longrightarrow s = (16 + 2 * 16) m

\longrightarrow s = ( 16 + 32 )m

\longrightarrow s = 48 m

8 0
3 years ago
An automatic dryer spins wet clothes at an angular speed of 4.1 rad/s. Starting from rest, the dryer reaches its operating speed
AleksandrR [38]

Answer:

The time taken by dryer to come up to speed of 4.1 rad/s is 0.95 s .

Explanation:

Given :

Initial angular speed , \omega_i=0\ rad/s .

Angular acceleration , \alpha=4.3\ rad/s^2 .

We need to find how much time it takes to reach a speed of 4.1 rad/s .

Therefore , applying equation of motion .

\omega_f-\omega_i=\alpha\times t\\\\4.1-0=4.3\times t\\\\t=\dfrac{4.1}{4.3}\ s\\\\t=0.95\ s

The time taken by dryer to come up to speed of 4.1 rad/s is 0.95 s .

3 0
3 years ago
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