Answer:
a) 6.5
b) pressure decreases
c)22 atm
Explanation:
Since the initial volume V1 is 5.40 L and the final volume V2 is 35.1 L, the ratio of V2:V1= 35.1/5.40= 6.5 hence the volume increases by a factor of 6.5.
When the volume increases, the pressure decreases accordingly in accordance with Boyle's law. Boyle's law states that the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.
c) From Boyle's law
Initial volume V1= 5.40 L
Final volume V2= 35.1 L
Initial pressure P1= 143 ATM
Final pressure P2 = the unknown
P1V1= P2V2
P2= P1V1/V2
P2 = 143 × 5.40/ 35.1
P2= 22 atm
The answer to this question would be B. hydrogen.
Two polar molecules can make hydrogen bond which was found in many polar molecules.
One example of hydrogen bond would be in the water. Water is a polar molecule with a positive end at the hydrogen side. Hydrogen bond in water is formed by molecule to molecule bond that looks like tetrahedral.
Answer:
A copper cup with a mass of 100.0 g contains 96.0 g of water. Both. the cup and the water are at 13.0OC. If 70.0 g of a substance at 84.0OC is added to the cup, the temperature increases to 20.0OC. If the specific heat capacities of copper and water are exactly 390 and 4180 respectively, find the specific heat capacity of the substance.
Explanation:
hope this helps
The correct answer is (B) Adding a dilute solution of HCl
<u>EXPLANATION</u>
The presence of carbonate ions can be tested by adding a dilute acid to the solution. The acid displaces Carbon (IV) oxide from the solution. Using HCl, and a carbonate of metal X.
XCO₃₍s₎ + 2HCl₍aq₎⇒ XCl₂₍aq₎+ H₂O₍l₎ + CO₂₍g₎
The gas produced is tested using calcium hydroxide to confirm whether it is carbon (IV) oxide.
Answer:
Explanation:
All the gases at the same temperature and mass have the same average kinetic energy.
If the masses were different, then the different gases will have different velocities. If the temperature was higher then there would be a greater motion, if the temperature was lower, then there would be less motion.