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madreJ [45]
3 years ago
7

By looking at the relative positions of the elements calcium, Ca, fluorine, F, sulfur, S, and oxygen, O, in the Periodic Table,

which TWO descriptions are TRUE about calcium fluoride, CaF2, and sulfur dioxide, SO2?
CaF2 is an ionic compound, and SO2i is a covalent compound.


CaF2 is formed by covalent bonds, and SO2 is formed by ionic bonds.


CaF2 cannot conduct electricity when dissolved in water, but SO2 can.


CaF2 is a gas at room temperature, while SO2 has a high boiling point.


CaF2 has a high boiling point, while SO2 is a gas at room temperature.


CaF2 is soft at room temperature, while SO2 is hard and forms crystals.
Physics
1 answer:
babymother [125]3 years ago
7 0

Answer:

B

Explanation:

i got B for my answer sorry if wrong

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Answer:van der Waals forces

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PLEASE HELP ME WITH THIS ONE QUESTION
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Answer:

B) R1 = 6 V and R2 = 6V

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Select the statement that best describes how the forces relate. A. All forces begin equally and become varied. B. The object on
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4 years ago
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A train leaves the station heading west on the tracks. It takes the train 8 seconds to reach 80 miles per hour. It completes the
Darina [25.2K]
 im not sure about most of this but ill try to help

so there are three formulas you need to know first: the formula for rate distance and time.

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to find time:
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and to find rate (which is what we need)
rate = distance / time


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8 0
4 years ago
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A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel
larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\      (1)

R1 =  13 Ω

R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}            (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

R_{eq}=\frac{23V}{4A}=5.75\Omega

Now, you can calculate the unknown resistor R2 by using the equation (1):

\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega

hence, the resistance of the unknown resistor is 10.31Ω

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3 years ago
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