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ddd [48]
4 years ago
10

A train leaves the station heading west on the tracks. It takes the train 8 seconds to reach 80 miles per hour. It completes the

entire 160 mile trip in two hours. Calculate the train's average speed and velocity over the two hour trip. Show your work. Identify if Each of the measurements are a scalar or vector quantity.
It needs work not just a simple answer I'm confused on it and I would like to know how to break it down
Physics
2 answers:
Darina [25.2K]4 years ago
8 0
 im not sure about most of this but ill try to help

so there are three formulas you need to know first: the formula for rate distance and time.

to find distance:
distance = rate * time

to find time:
time = distance / rate

and to find rate (which is what we need)
rate = distance / time


now we just use our formula and plug in the numbers

rate = distance * time

rate = 160 / 2 = 80

so our rate is 80. thats all i know i have no idea about the rest but i always use these messurments. im sure you can google most of it to get other formulas and calculators though. sorry i couldnt help much! good luck :D
melomori [17]4 years ago
3 0

Answer:

80 miles per hour

Explanation:

Average speed is defined as the ratio of total distance traveled by the total time taken.

Average speed = total distance traveled / total time taken

Its S.I. unit is m/s and it is a scalar quantity.

Average velocity is defined as the ratio of total displacement covered to the total time taken.

Average velocity = total displacement covered / total time taken

Its S.I. unit is m/s and it is a vector quantity.

According to the question, the displacement and the distance both are same as the train travels in a straight line.

Total distance = total displacement = 160 miles

Total time = 2 hours

Average speed = 160 / 2 = 80 miles per hour

Average velocity = 160 / 2 = 80 miles per hour

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icang [17]

Answer:

Part a)

P = 5.72 kg m/s

Part b)

\Delta P = 2.93 kg m/s

Part c)

F = 44.4 N

Part d)

\Delta P = 5.02 kg m/s

Part e)

\Delta t = 0.113 s

Part f)

\Delta K = 0

Explanation:

As we know that initial velocity of the ball is given as

v = 11.8 cos29 \hat i + 11.8 sin29 \hat j

v_i = 10.3 \hat i + 5.72 \hat j

Now final velocity of the system is given as

v_f = 10.3\hat i - 5.72\hat j

Part a)

now magnitude of initial momentum is given as

P = mv

P = 0.256(11.8)

P = 5.72 kg m/s

Part b)

Change in momentum is given as

\Delta P = m(v_f - v_i)

\Delta P = 0.256(5.72 + 5.72)

\Delta P = 2.93 kg m/s

Part c)

As we know that average force is defined as the rate of change in momentum

so here we have

F = \frac{\Delta P}{\Delta t}

F = \frac{2.93}{0.066}

F = 44.4 N

Part d)

Magnitude of change in momentum is given as

\Delta P = m(v_f - v_i)

\Delta P = 0.256(7.8 + 11.8)

\Delta P = 5.02 kg m/s

Part e)

As we know that in 2nd case the force is same as the initial force

so we will have

\frac{\Delta P}{\Delta t} = F

\frac{5.02}{\Delta t} = 44.4

\Delta t = 0.113 s

Part f)

Since this is elastic collision so change in kinetic energy must be ZERO

\Delta K = 0

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Momentum is a vector quantity, and is always conserved. Whenever a collision occurs between two objects, the objects behave under the principle of conservation of momentum. Therefore, if an object moves in the direction opposite to its original direction after a collision, then this indicates that the momentum of the colliding object was greater than the object under consideration. 
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Sarah, whose mass is 40 kg, is on her way to school after a winter storm when she accidentally slips on a patch of ice whose coe
RideAnS [48]

Sarah's acceleration is -0.49 m/s^2

Explanation:

The force of kinetic friction acting on Sarah has a magnitude which is given by:

F_f = \mu mg

where

\mu is the coefficient of kinetic friction

m is Sarah's mass

g is the acceleration of gravity

Moreover, according to Newton's second law of motion, we know that the net force on Sarah is equal to its mass times its acceleration:

F=ma

where a is the acceleration

Since the force of friction is the only force acting on Sarah, we can say that the net force is equal to the force of friction, therefore:

F=-\mu mg = ma

where the negative sign is due to the fact that the force of friction has a direction opposite to the motion of Sarah. Solving for a, we find

a=-\mu g

And substituting the following values:

\mu = 0.05 (coefficient of friction)

g=9.81 m/s^2 (acceleration of gravity)

we find:

a=-(0.05)(9.81)=-0.49 m/s^2

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

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4 0
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Can someone please help out :/
beks73 [17]

Answer:

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