compounds. is the answer.
Answer:

Explanation:
In this problem, the temperature stays constant. The volume and pressure change, so we use Boyle's Law. This states that the pressure of a gas is inversely proportional to the volume. The formula is:

Now we can substitute any known values into the formula.
Originally, the gas has a volume of 25.0 liters and a pressure of 2.05 atmospheres.

The volume is decreased to 14.5 liters, but the pressure is unknown.

Since we are solving for the new pressure, or P₂, we must isolate the variable. It is being multiplied by 14.5 liters and the inverse of multiplication is division. Divide both sides by 14.5 L .


The units of liters cancel.



The original values of volume and pressure have 3 significant figures, so our answer must have the same.
For the number we found, that is the hundredth place.
The 4 in the thousandth place (in bold above) tells us to leave the 3 in the hundredth place.

The new pressure is approximately <u>3.53 atmospheres.</u>
We are given that:
1 atom N = 3 atom of the metal
1 mol N = 3 mol of the metal
First let us convert the given nitrogen into number of
moles:
moles N = 1 g / (14 g / mol)
moles N = 0.071 mol
Therefore the atomic or molar mass of the metal is:
molar mass = 1.486 g / (3 * 0.071 mol)
<span>molar mass = 6.93 g / mol</span>
Given data:
Mass of cesium chloride CsCl (m) = 52.3 g
Mass of water (mh2O)= 60.0 g
Volume of the solution (V) = 63.3 ml
Step 1: Calculate the number of moles of CsCl
Molar mass of CsCl = 168.36 g/mol
Mass of CsCl = 52.3 g
# moles = mass/molar mass = 52.3 g/168.36 g.mol-1 = 0.3106 moles
Step 2: Volume of solution in Liters
1000 ml = 1 liter
therefore, 63.3 ml corresponds to : 63.3 ml * 1 L/1000 ml = 0.0633 L
Step 3: Calculate molarity of CsCl
Molarity = moles of CsCl/volume of solution
= 0.3106 moles/0.0633 L = 4.91 moles/L
Molarity = 4.91 M