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Archy [21]
3 years ago
9

Please help! I need an answer ASAP, I will be marking brainliest.

Chemistry
2 answers:
aleksley [76]3 years ago
8 0
Yeah it’s definitely B
asambeis [7]3 years ago
6 0
B because A is for radios of course and C is thermal energy and D is radioactive
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4. The volume of a sample of a gas at STP is 200.0 ml. If the pressure is increased to 4.00 atmospheres (temperature constant),
Elina [12.6K]

Answer : The value of new volume is, 50.0 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure at STP = 1 atm

P_2 = final pressure =  4.00  atm

V_1 = initial volume at STP = 200.0 mL

V_2 = final volume = ?

Now put all the given values in the above equation, we get:

1atm\times 200.0mL=4.00atm\times V_2

V_2=50.0mL

Therefore, the value of new volume is, 50.0 mL

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4 years ago
39 which statement about the process of dissolving is TRUE
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C !!!!!!!!!!!!!!!!!!!!!!
6 0
3 years ago
Express 250,000 mL in liters.<br> A) 0.25 L <br> B) 2,500 L <br> C) 25 L <br> D) 250 L
elena-s [515]
D) 250l
Explanation :
250,000/1000
5 0
3 years ago
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Which of the following describes a covalent bond?
Marizza181 [45]

Answer:

D. It is the sharing of electrons between atoms with an electronegativity difference below 1.7

Covalent bonds share electrons, whereas ionic bonds exchange electrons. Covalent bonds have an electronegativity of 0.0-1.7 (0.0-0.3 is a nonpolar covalent bond and 0.3-1.7 is a polar covalent bond). Ionic bonds are bonds that go beyond the electronegativity of 1.7 to 4.0 (1.7-4.0).

7 0
3 years ago
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The Goodyear blimp contains 5.7 x 10^6 L of helium at 25 degrees Celsius and 1 atm. What is the mass in grams of the helium insi
anygoal [31]

Answer:

1.72x10⁻⁵ g

Explanation:

To solve this problem we use the PV=nRT equation, where:

  • P = 1 atm
  • V = 5.7x10⁶ L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 25 °C ⇒ (25+273.16) = 298.16 K

And we <u>solve for n</u>:

  • 1 atm * 5.7x10⁶ L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
  • n = 4.29x10⁻⁶ mol

Finally we <u>convert moles of helium to grams</u>, using its <em>molar mass</em>:

  • 4.29x10⁻⁶ mol * 4 g/mol = 1.72x10⁻⁵ g

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