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kotykmax [81]
3 years ago
8

Nick and Sally run on the 100m straight track,Nicks's speed is 3m/s,Sally's soeed is 2m/s.If they both start from two sides of t

he track, running towards each other continuously.Then they would meet each other ... times after 10 minutes
Mathematics
1 answer:
Pepsi [2]3 years ago
4 0

They would meet 30 times after 10 minutes.

Since Nick and Sally run on the 100m straight track, and Nicks's speed is 3m / s, while Sally's speed is 2m / s, if they both start from two sides of the track, running towards each other continuously, to determine how many times they would meet each other after 10 minutes the following calculation should be performed:  

  • 30 x 20 + 2 x 20 = 60 + 40 = 100
  • 10 minutes = 600 seconds
  • 600/20 = X
  • 30 = X

Therefore, they would meet 30 times after 10 minutes.

Learn more about maths in brainly.com/question/25849676

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According to the Rational Root Theorem, which number is a potential root of f(x) = 9x8 + 9x6 – 12x + 7?
notsponge [240]

<u>Answer-</u>

\boxed{\boxed{\frac{7}{3}}}

<u>Solution-</u>

Rational Root Theorem-

f(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+.......+a_1x+a_0\ \ \ and\ a_n\neq 0

All the potential rational roots are,

=\pm (\dfrac{\text{factors of}\ a_0}{\text{factors of}\ a_n})

The given polynomial is,

f(x) = 9x^8 + 9x^6-12x + 7

Here,

a_n=9,\ a_0=7\\\\\text{factors of}\ 9=1,3,9\\\\\text{factors of}\ 7=1,7

The potential rational roots are,

=\pm \frac{1}{1},\pm \frac{1}{3}, \pm \frac{1}{9}, \pm \frac{7}{1}, \pm \frac{7}{3}, \pm \frac{7}{9}

=\pm 1,\pm \frac{1}{3}, \pm \frac{1}{9}, \pm 7, \pm \frac{7}{3}, \pm \frac{7}{9}

From, the given options only \frac{7}{3} satisfies.

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3 years ago
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Afina-wow [57]

Answer:

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Step-by-step explanation:

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What’s the volume of this triangular prism ?
iris [78.8K]

Answer: 157.5

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Step-by-step explanation:

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A teacher was interested in finding out whether a special study program would increase the scores of students on a national exam
bija089 [108]

Answer:

Check the explanation

Step-by-step explanation:

Going by the first attached image below we reject H_o against  H_1 if obs.T > t_{\alpha /2;n-1}

here obs.T=1.879

\therefore obs.T \ngtr 2.447=t_{0.025;6}

we accept H_o:\mu _{1}=\mu_{2} at 5% level of significance.

i.e there is no sufficient evidence to indicate that the special study program is more effective at 5% level of significance.

1.

this problem is simillar to the previous one except the alternative hypothesis.

Let X_i's denote the bonuses given by female managers and Y_i's denote the bonuses given by male managers.

we assume that X_i \sim N(\mu _{1},\sigma _{1}^{2}) Y_i \sim N(\mu _{2},\sigma _{2}^{2}) independently

We want to test H_0:\mu_{1}=\mu_{2} vs H_1:\mu_{1}\neq \mu_{2}

define D_i=X_i-Y_i , i=1(1)8

now D_i\sim N(\mu _{1}-\mu _{2}=\mu _{D},\sigma _{1}^{2}+\sigma _{2}^{2}=\sigma _{D}^{2}) , i=1(1)8

the hypothesis becomes

H_0:\mu_{D}=0 vs H_1:\mu_{D}\neq 0

in the third attached image, we use the same test statistic as before

i.e at 5% level of significance there is not enough evidence to indicate a difference in average bonuses .

3 0
3 years ago
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