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san4es73 [151]
2 years ago
6

Need help with this math that I don’t know

Mathematics
2 answers:
denis23 [38]2 years ago
6 0

Answer:

$129.00

Step-by-step explanation:

First, we find out the area of the window

(2+6)/2 =4

4*1.5= 6 ft ^2

6*21.5= $129.00

FromTheMoon [43]2 years ago
5 0

Answer:

6 sqft × $21.5 = $129

Step-by-step explanation:

Area of a trapezoid is just average the top and bottom 2 + 6 = 8÷2 = 4 the times this by the height. So toss out those 2.5 sides (the not-parallel sides) we don't need them; we don't care about them. Use the straight up and down height measurement.

4 × 1.5

= 6 ft^2

Then times by 21.50 to find the cost. 6×21.5=129

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A password is 4 characters long and must consist of 3 letters and 1 of 10 special characters. If letters can be repeated and the
Ne4ueva [31]

The number of possibilities for constructing the 4 characters long password with specified conditions is given by: Option C: 703,040

<h3>What is the rule of product in combinatorics?</h3>

If a work A can be done in p ways, and another work B can be done in q ways, then both A and B can be done in p \times q ways.

Remember that this count doesn't differentiate between order of doing A first or B first then doing other work after the first work.

Thus, doing A then B is considered same as doing B then A

We're specified that:

  • The password needs to be 4 characters long
  • It must have 3 letters and 1 of 10 special characters.
  • Repetition is allowed.

So, each of 3 characters get 26 ways of being 1 letter. (assuming no difference is there between upper case letter and lower case letter).

And that 1 remaining character get 10 ways of being a special character.

So, by product rule, this choice (without ordering) can be done in:

26 \times 26 \times 26 \times 10 = 175760 ways.

Now, the password may look like one of those:

  1. L, L, L, S
  2. L, L, S, L
  3. L, S, L, L
  4. S, L, L, L

where S shows presence of special character and L shows presence of letter.

Those 175760 ways are available for each of those four ways.

Thus, resultant number of ways this can be done is:

175760 \times 4 = 703040

Thus, the number of possibilities for constructing the 4 characters long password with specified conditions is given by: Option C: 703,040

Learn more about rule of product here:

brainly.com/question/2763785

5 0
1 year ago
Answer please. Simplify the expression<br><br> 8y - 11y + 6
sattari [20]
8y - 11y + 6

Combine like terms

-3y + 6 is the simplified answer. 
5 0
2 years ago
Help please show work
Aleonysh [2.5K]

Answer:

C. 56.25π

Step-by-step explanation:

Circumference=15π=πd⇒d=15

Area=πr^2⇒r=d/2⇒r=7.5⇒π7.5^2=56.25π

7 0
2 years ago
Karan needs to choose between two gym plans. he can either pay a $150 joining fee and a $10 monthly fee, or he can pay a $50 joi
Eva8 [605]

Solution:

Let the cumulative costs of the plans will be equal after x months.

Then we can write

150+10x=50+300x\\ \\ 150-50=300x-10x\\ \\ 100=290x\\ \\ x=\frac{100}{290}\\ \\ x=\frac{10}{29}

Hence after 10/29th Month cost will be equal.

and that cost=150+\frac{10}{29} *10=\frac{4450}{29} $

3 0
3 years ago
If angle 2 measures 155 degrees in the image below and what is the measurement of angle 1
Degger [83]
<h2>Answer:</h2>

<em>Angle 1 measures 25 degrees</em>

<h2>Explanation:</h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Here I'll assume the diagram shown below. In that figure, we know that:

\angle 1=? \\ \\ \angle 2=155^{\circ}

The figure shows that these two angles are supplementary, so they add up to 180 degrees. Therefore:

\angle 1+\angle 2=180^{\circ} \\ \\ Substituting \ \angle 2=155^{\circ}: \\ \\ \angle 1+155^{\circ}=180^{\circ} \\ \\ \\ Isolating \ \angle 1: \\ \\ \angle 1=180^{\circ}-155^{\circ} \\ \\ \boxed{\angle 1=25^{\circ}}

4 0
3 years ago
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