Answer:
a) <u>310.18 g/mol</u>
<u>b) 4.352 moles Ca3(PO4)2</u>
<u>c) 2.6 * 10^24 molecules</u>
<u>d) 5.24 * 10^24 P atoms</u>
<u>e)13.056 moles Ca</u>
<u>f)</u>10825.3 grams
Explanation:
Step 1: Data given
Atomic mass of Ca = 40.08 g/mol
Atomic mass of P = 30.97 g/mol
Atomic mass of O = 16.0 g/mol
Step 2: Calculate molecular weight of Ca3(PO4)2
Molecular weight of Ca3(PO4)2 = 3*atomic mass of Ca + 2* atomic mass of P and 8* atomic mass of O
Molecular weight of Ca3(PO4)2 = 3*40.08 + 2*30.97 + 8*16.0 =<u> 310.18 g/mol</u>
Step 3: Calculate moles of Ca3(PO4)2 in 1350 grams
Moles Ca3(PO4)2 = mass Ca3(PO4)2 /molar mass
Moles Ca3(PO4)2 = 1350 grams / 310.18 g/mol
Moles Ca3(PO4)2 = <u>4.352 moles</u>
Step 4: Calculate molecules in 1350 grams
Molecules = moles * number of Avogadro
Molecules = 4.352 moles * 6.02 * 10^23
Molecules = <u>2.6 *10^24 molecules</u>
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Step 5: Calculate moles Phosphorus
For 1 mol Ca3(PO4)2 we need 2 moles P
For 4.352 moles Ca3(PO4)2 we have 2*4.352 = 8.704 moles
Step 6: Calculate P atoms
Atoms P = 8.704 moles * 6.02*10^23
Atoms P =<u> 5.24 * 10^24 P atoms</u>
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Step 7: Calculate moles Calcium in 1350 grams
For 1 mol Ca3(PO4)2 we have 3 moles Ca
For 4.352 moles we have 3*4.352 = <u>13.056 moles Ca</u>
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<u>Step 8:</u> Calculate mass of 2.1 * 10^25 molecules of Ca3(PO4)2
Moles Ca3(PO4)2 = 2.1 * 10^25 / 6.02 * 10^23
Moles Ca3(PO4)2 = 34.9 moles
Mass Ca3(PO4)2 = 34.9 moles * 310.18 g/mol
Mass Ca3(PO4)2 = 10825.3 grams