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3 years ago

Which technology is used to deal with waste management?

1 answer:

4 0

D) recycling ;)

Waste Management's Aerobic-Anaerobic Bioreactor* is designed to accelerate waste degradation by combining attributes of the aerobic and anaerobic bioreactors. The objective of the sequential aerobic-anaerobic treatment is to cause the rapid biodegradation of food and other easily degradable waste in the aerobic stage in order to reduce the production of organic acids in the anaerobic stage resulting in the earlier onset of methanogenesis. In this system the uppermost lift or layer of waste is aerated, while the lift immediately below it receives liquids. Landfill gas is extracted from each lift below the lift receiving liquids. Horizontal wells that are installed in each lift during landfill construction are used convey the air, liquids, and landfill gas. The principle advantage of the hybrid approach is that it combines the operational simplicity of the anaerobic process with the treatment efficiency of the aerobic process. Added benefits include an expanded potential for destruction of volatile organic compounds in the waste mass. (*US Patent 6,283,676 B1)

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You are a chemist working in your laboratory. In your storage closet you have a

Nastasia [14]

Ans is B.Bromine. Only two elements are liquid at room temperature ( mercury and Bromine) . Helium and chlorine, arsenic are gases.

8 0

3 years ago

The table above shows the number of protons in an Adam of four different elements according to the periodic table which of these

Maurinko [17]

Answer:

The correct answer is X

Explanation:

First have some idea about : Valency , Metals and non- metals.

Valency : It is the combining capacity of elements . The elements combine to other elements to gain stability . They always try to complete their octet(8 electrons in the outermost shell)

For Example : Na has 11 electron

Its electronic configuration is : 2 ,8 ,1 (2+8+1 = 11)

First shell contain maximum = 2 electron

2nd shell = maximum 8 electron

3 shell = maximum 18 electron

When it remove 1 electron from outermost shell , it is left with 2 ,8 configuration. Now , its outer most shell has 8 electron . so it get stable and show +1 valency.

When the element looses electron , it get positive charge

When the element gain electron it get negative charge

Metals: those element which show +1 , +2 , +3 valency are considered as metals

Non- metals = Those metals which show the valency of -1 , -2 ,-3 are considered as Non- Metals.

Questions:

1. T = 7 proton

Electronic configuration = 2 , 5

It gains (-ve charge) 3 electron to achieve complete octet(5+3 = 8) = -3 valency

It is non- metal

2. Q=15

Its electronic configuration = 2 ,8 , 5

It gains (-ve charge) 3 electron to achieve complete octet(5+3 = 8) = -3 valency

It is non- metal

3.X = 12

Its electronic configuration = 2 ,8 , 2

It loses (+ve charge) 2 electron to achieve complete octet( 2 , 8) = + 2 valency

It is metal

4.Z = 17

Its electronic configuration = 2 ,8 , 7

It gains (-ve charge) 1 electron to achieve complete octet(7+1 = 8) = -1 valency

It is non- metal

There is only one metal = X

4 0

3 years ago

Enter the chemical formula of a binary molecular compound of hydrogen and a Group 6A element that can reasonably be expected to

Ber [7]

Answer:

H₂Se

Explanation:

A way of estimating the acidity of a weak acid is by analizing the stability of the formed anion. In this case, we should find a Group 6A element that in its anionic forms (HX⁻ and X⁻²) is more stable than HS⁻ and S⁻², thus it would be more acidic in aqueous solution.

The anionic forms of Se are more stable than the forms of S, similarly to how Br⁻ is more stable than Cl⁻.

8 0

3 years ago

For an object to remain at rest, which of the following must be true?

zubka84 [21]

Answer:

the forces on it are balanced

Explanation:

7 0

3 years ago

Read 2 more answers

Magicians often use ‘flash powder’ in their acts. Flash powder contains 69.0% potassium chlorate (31.9% K, 28.9% Cl, 39.2% O) an

mafiozo [28]

Answer:

$\rm K$ : approximately $22.0\%$ .

$\rm Cl$ : approximately $19.9\%$ .

$\rm O$ : approximately $27.0\%$ .

$\rm Al$ : $31.0\%$ .

Explanation:

Consider a $100\; \rm g$ sample. There would be $69.0\% \times 100\; \rm g = 69.0\; \rm g$ of $\rm KClO_{3}$ and $100.0\; \rm g - 69.0\; \rm g = 31.0\; \rm g$ of $\rm Al$ .

Out of that $69.0\; \rm g$ of $\rm KClO_{3}$ :

$31.9\%$ (by mass) would be $\rm K$ : $31.9\% \times 69.0\; \rm g \approx 22.0\; \rm g$ .

$28.9\%$ (by mass) would be $\rm Cl$ : $28.9\% \times 69.0\; \rm g \approx 19.9\; \rm g$ .

$39.2\%$ (by mass) would be $\rm O$ : $39.2\% \times 69.0\; \rm g \approx 27.0\; \rm g$ .

Overall, the composition (by mass) of each element in this mixture would be:

$\rm K$ :

$\begin{aligned} & \frac{31.9\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 31.9\% \times 69.0\% \\ \approx \; & 22.0\%\end{aligned}$ .

$\rm Cl$ :

$\begin{aligned} & \frac{28.9\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 28.9\% \times 69.0\% \\ \approx \; & 19.9\%\end{aligned}$ .

$\rm O$ :

$\begin{aligned} & \frac{39.2\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 39.2\% \times 69.0\% \\ \approx \; & 27.0\%\end{aligned}$ .

$\rm Al$ :

$\begin{aligned}& \frac{100\; \rm g - 69.0\; \rm g}{100\; \rm g} \\ =\; & 100\% - 69.0\% \\ =\; & 31.0\%\end{aligned}$ .

7 0

3 years ago