ANSWER
(3, 11) and (−3, −7)
EXPLANATION
The given system of equations are:

and

or

We equate the two equations to obtain,

We rewrite in standard quadratic form to obtain,

This simplifies to

We solve for x to obtain,




When


When x=-3,

Therefore the solution for the system is (3, 11) and (−3, −7).
Answer:The Sine function:
f
(
x
)
=
sin
(
x
)
The Cosine function:
f
(
x
)
=
cos
(
x
)
and
The Logistic function:
f
(
x
)
=
1
1
−
e
−
x
are the only function of the "Basic Twelve Functions" which are bounded above.
Step-by-step explanation:
<h3>
Answer: 
</h3>
Explanation:
The identity we'll use is cos(-x) = cos(x) for any value of x.
So cos(-150) = cos(150).
Then locate the angle 150 on the unit circle. The terminal point is 
The x coordinate of this terminal point is the value of cos(150).
Answer:
1
Step-by-step explanation:
Here f(x) = x^2 - 2x - 5, which at x - -5 is 25 +10 - 5 = 30 and at x = 6 is 19.
The average value of a function f(x) over an interval [a, b] is
f(b) - f(a)
ave. val. = ---------------
b - a
which in this particular case is
19 - 30
ave. val. = ----------------- = -11/11 = 1
6 - (-5)
The average value of this function f(x) = x^2 - 2x - 5 on [-5, 6] is 1.