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77julia77 [94]
2 years ago
14

Watch help video

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
4 0

Answer:

\frac{x^4-x^3-19x^2-10x+17}{x-5}=x^3+4x^2+x-5+\frac{-8}{x-5}

Step-by-step explanation:

5 | 1  -1  -19  -10   17

___<u>   5  20_ 5  -25____</u>

    1   4    1   -5  | -8

So, we show our answer as 1x^3+4x^2+1x-5+\frac{-8}{x-5}=x^3+4x^2+x-5+\frac{-8}{x-5}

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Which of the following expressions results in 0 when evaluated at x = 4?
fenix001 [56]

The answer is B. because (4-10) equals -6 and (4-4) equals 0. -6 times 0 is 0.

3 0
3 years ago
raul bought 2 packs of erasers he found 2 erasers in his backpack now raul has 8 erasers were in each pack?
r-ruslan [8.4K]
There was 3 erasers in each pack because 2 times 3 is 6 plus 2 equals 8. so there are 3 in each pack.
7 0
3 years ago
Read 2 more answers
Determine the domain of the function (fog) (x) where f(x) = 3x-1/x-4 and g(x)=x+1/x
Mrac [35]

Answer:

(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)

Step-by-step explanation:

The given functions are f(x)=\frac{3x-1}{x-4} and g(x)=\frac{x+1}{x} .

We now composed the two functions to find:

(f\circ g)(x)=f(g(x))

\implies (f\circ g)(x)=f(\frac{x+1}{x})

\implies (f\circ g)(x)=\frac{3(\frac{x+1}{x})+1}{\frac{x+1}{x}-4}

\implies (f\circ g)(x)=\frac{4x+3}{1-3x}

This function is defined if the denominator is not zero.

1-3x\ne0

x\ne\frac{1}{3}

We write this in interval notation as:

(-\infty,\frac{1}{3})\cup (\frac{1}{3},\infty)

We need to be cautious here as x=0 is not in the domain of g(x).

Therefore the domain of (f\circ g)(x) is

(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)

4 0
3 years ago
A circle is centered at the point (-7,-1) and passes through the point (8, 7). The radius of the circle is ___ units. The point
trapecia [35]

Answer:

(x + 7)2 + (y + 1)2 = r2.

To get we use point (8, 7): (8 + 7)2 + (7 + 1)2 = r2, r2 = 225 + 64 = 289 = 172.

So, equation of circle: (x + 7)2 + (y + 1)2 = 289

Step-by-step explanation:

5 0
3 years ago
You purchase a car in 2010 for $25,000. The value of the car decreases by 14% annually. What would the value of the car be in 20
Fed [463]

Answer: -$6,500

Step-by-step explanation:

Here we could , use the arithmetic progression where

T(2020 - 2010) = a + ( n - 1 )d

T10 = a + ( 10 - 1 )d --------------- 1

a = $25,000, n = 10 and d = 14% of $25,000 = $3,500 the common difference.

Note since it decreases the common difference d = -$3,500.

Now substitute for the values in the equation above.

T10 = 25,000 + 9 x -3,500

= $25,000 - $31,500

= -$6,500 (deficit )

4 0
3 years ago
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