<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-x-56%5C%5C" id="TexFormula1" title="x^{2} -x-56\\" alt="x^{2} -x-56\\" align="a

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3 years ago

bsmiddle" class="latex-formula">

1 answer:

4 0

Answer:

(x - 8)(x + 7)

Zeroes: x = 8, x = -7

Step-by-step explanation:

Find factors of -56 that add to -1.

-8 and 7

The factored form is:

(x - 8)(x + 7)

The zeroes for this polynomial are x = 8 and x = -7

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