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Juli2301 [7.4K]
3 years ago
13

Why is acceleration of an object moving at a constant velocity always zero?

Physics
1 answer:
k0ka [10]3 years ago
8 0

Answer:

If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).

Explanation:

In the middle, when the object was changing position at a constant velocity, the acceleration was 0. This is because the object is no longer changing its velocity and is moving at a constant rate.

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I WILL MAKE U BRAINLIEST PLEASE ANSWER !!!!!!!!
Nesterboy [21]

Answer:

125÷2= 62.5 is your average speed. If the train was resting it's not moving your going nowhere . If the train is traveling at constant speed in a straight line it's speed will increase going through mountains will slow it down. if the train is coming to a braking force its speed will decrease

3 0
3 years ago
16. A pug puppy is sitting on a skateboard. The pug has a mass of 2.4 kg, and the skateboard has a mass
kramer

Answer:

12 N

Explanation:

Use Newton's second law:

∑F = ma

F = (2.4 kg + 1.3 kg) (3.2 m/s²)

F = 11.84 N

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3 years ago
Select the correct answer.
Ilia_Sergeevich [38]
Pretty sure it is B.
Because inertia is a tendency to do nothing or remain unchanged.
8 0
2 years ago
A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. The driver sees a small gap between a van and a
masya89 [10]

Answer:

1

  a =  2.82 \  m/s^2

2

 t =  8.87 \  s

3

 s =  204 \  m

Explanation:

From the question we are told that

   The  speed of the car is  v  =  25.0 \  m/s

   The length of the ramp is  d =  111 \ m

   The  constant velocity of the traffic v_t  =  23.0 \  m/s

Generally the acceleration of the car is mathematically represented as

           a =  \frac{v^2  -  u^2 }{2d}

Here  u is  equal to zero given that the car started from rest so

           a =  \frac{25^2 - 0^2 }{2 *  111}

       =>    a =  2.82 \  m/s^2

Generally the time taken is mathematically represented as

      t = \frac{ v - u}{ a}

=>   t  = \frac{ 25 - 0}{2.82}

=>   t =  8.87 \  s

The  distance traveled by the traffic is mathematically represented as

  s =  v_{t}t + \frac{1}{2} a t^2

Here  a is zero given that the traffic was moving at constant speed

=>    s  =  23 *  8.87

=>     s =  204 \  m

7 0
3 years ago
Four wire AB,BC,CD and DA each resistance 4 ohm and a fifth wire BD of resistance 8 ohm are joined to form a rectangle to which
Anarel [89]
Since it's so late, and it's way past my bedtime, and I'm tired and hungry,
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Ready ?

Here goes:

The effective resistance between points 'A' and 'B' is (2 and 2/3) Ω .
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