F=ma which is newtons second law. so we have here a=g in this situation and g=gravity and that equals 9.80m/s^2 on earth surface. So we have F=5.7kg*9.80m/s^2=55.9N or Newtons. Thank You! Please rate!
Answer:
10.36m/s
Explanation:
From the question we are given;
Distance S = 5.40m
Initial velocity v= 1.17m/s
Required
Final velocity of the diver
Using the equation of motion
v² = u²+2gS
v²= 1.17²+2(9.8)(5.40)
v² = 1.3689+105.84
v² = 107.2089
v = √107.2089
v= 10.36m/s
Hence the required velocity is 10.36m/s
Time taken by the ball to reach the ground is 1.8s.
<h3>What is free falling?</h3>
When an object is released from rest in free air considering no friction, the motion is depend only on the acceleration due to gravity, g.
A ball is thrown directly downward with an initial speed of 7.30 m/s, from a height of 29.0 m
Using the second equation of motion,
s = ut + 1/2 at²
Plug the values, we get
29 = 7.3t + 1/2 x9.81t²
4.905t² + 7.3t -29 =0
t =1.79871 or −3.28699
As time can't be negative, time taken to strike the ground is approximately 1.8 s.
Learn more about free falling.
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The unit of pressure in the SI system is the pascal (Pa), defined as a force of one Newton per square meter.
Here is the first question