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BaLLatris [955]
3 years ago
6

Our Sun will eventually:

Physics
2 answers:
puteri [66]3 years ago
5 0

Answer:

B. Become a white dwarf star.

Explanation:

As the Sun is a medium size star in mid of its life of around 10 Billion years. When it will exhaust all the Hydrogen in the core, it will go through a long process of death: Converting into a red giant to Planetary Nebula to a white dwarf. It will spend trilliion of years in white dwarf phase before fading and converting to a Black dwarf.

If it had been a massive star it would have made a Supernova and then ultimately a black hole or a neutron star.

nasty-shy [4]3 years ago
3 0

B. become a white dwarf star

It will swell, shed its layers, and become a white dwarf star.

I know the sun does not have enough mass to become a supernova or a black hole.

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You are an astronomer and are making observations about a visible but faraway galaxy. Describe what evidence you could gather to
Pavel [41]

Answer:

Chemical Composition

The chemical composition of the Universe is dominated by the hydrogen and helium produced in the Big Bang. The remaining 90 or so chemical elements are produced in stars and constitute only a few percent of the overall mass. Astronomers refer to these elements (all except hydrogen and helium) as metals, even though this includes elements such as carbon and oxygen which are not considered metals in the normal sense.

The abundance of metals with respect to hydrogen is known as the metallicity. While hydrogen and helium are found in high abundance throughout the Universe, the metallicity varies depending on the history of star formation in the region. The chemical composition of the Sun gives us some idea of the chemical composition of the solar neighbourhood:

Chemical composition of the Sun

Hydrogen 73%

Helium 25%

Oxygen 0.80%

Carbon 0.36%

Iron 0.16%

Neon 0.12%

Nitrogen 0.09%

Silicon 0.07%

Magnesium 0.05%

Sulphur 0.04%

Others combined 0.04%

This indicates that metals constitute only about 2% of the Sun’s mass.

The highest metallicities are found in the centres of galaxies. For example, near the centre of the Milky Way, stars with metallicities of up to three times the solar value have been observed. However, there are also stars with only 1/10,000th of the solar value. These stars formed early in the history of the Galaxy, before the interstellar medium (and subsequent generations of stars) became enriched in metals through the actions of other stars.

Although never more than a few percent by mass, the metals content of stars has a significant effect on their stellar evolution, with metal-rich stars being cooler, larger and longer-lived than metal-poor stars of the same mass. Both the length of time spent on the main sequence and the detail of post-main sequence evolution are significantly affected by a star’s metallicity.

To fully describe the chemical composition of stars (or galaxies) it is also necessary to define abundance ratios. These relate the relative abundances of metals to each other (e.g. the abundance ratio of magnesium to iron or carbon to oxygen). Astronomers use these abundance ratios to measure how long the object in question has been forming stars.

Both metallicities and abundance ratios are usually expressed in terms of the values for the Sun, and normally on a logarithmic scale.

6 0
1 year ago
An engine that has an efficiency of 25% takes in 200 [J] of heat during each cycle. Calculate the amount of work this engine per
BartSMP [9]

Answer:

W=50J

Explanation:

The work done W and the energy taken Q_{in} by a heat engine are related to the efficiency \eta by the expression

\eta=\frac{W}{Q_{in}}

The efficiency is \eta=25%, the numerical form of this percentage is 0.25 and the energy taken is Q_{in}=200J. Replacing in the formula:

0.25=\frac{W}{200}\\W=200*0.25\\W=50J

5 0
3 years ago
An electron is released from rest at a distance of 0.300 m from a large insulating sheet of charge that has uniform surface char
jarptica [38.1K]
Yes that is the correct answer
8 0
3 years ago
Does the force of kinetic friction depend on the weight of the block? explain.
drek231 [11]
Yes for an object moving on a horizontal plane, R = mg (where mg = weight). therefore, for an object moving on a horizontal plane: F = μmg



7 0
2 years ago
A person wearing a shoulder harness can survive a car crash if the acceleration is smaller than -300 m/s . assuming constant acc
mars1129 [50]

To solve this problem, we use the equation:

<span>d = (v^2  - v0^2) / 2a</span>

 

where,

d = distance of collapse

v0 = initial velocity = 101 km / h = 28.06 m / s

v = final velocity = 0

a = acceleration = - 300 m / s^2

 

d = (-28.06 m / s)^2 / (2 * - 300 m / s^2)

<span>d = 1.31 m</span>

3 0
2 years ago
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