What mass of sodium chloride is needed to prepare 200 ml of a 0.1 M solution
2 answers:
Answer:
C. 1.17 grams
Explanation:
The molarity is the no. of moles of solute in a 1.0 L of the solution. <em>M = (mass/molar mass)solute x (1000/ V) </em>
M = 0.1 M, mass = ??? g , molar mass of NaCl = 58.44 g/mol, V = 200.0 mL.
∴ mass of NaCl = (M)(molar mass)(V)/1000 = (0.1 M)(58.44 g/mol)(200.0 mL)/1000 = 1.168 g ≅ 1.17 g.
<h2>Answer:</h2>
<u>The right choice is </u><u>(C) 1.17 grams </u><u> </u>
<h2>Explanation:</h2>
As we know
c = n/V
n = c * V
n = m/M
m = c* V * M
m = 0.1mol/L * 0.2 L * 58.44 g/mol
m = 1.1688 g ≈ 1.17 g
So the mass of NaCl needed will be 1.17 grams
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