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Lesechka [4]
3 years ago
10

What mass of sodium chloride is needed to prepare 200 ml of a 0.1 M solution

Chemistry
2 answers:
Nikolay [14]3 years ago
5 0

Answer:

C. 1.17 grams

Explanation:

  • The molarity is the no. of moles of solute in a 1.0 L of the solution.

<em>M = (mass/molar mass)solute x (1000/ V)</em>

M = 0.1 M, mass = ??? g, molar mass of NaCl = 58.44 g/mol, V = 200.0 mL.

∴ mass of NaCl = (M)(molar mass)(V)/1000 = (0.1 M)(58.44 g/mol)(200.0 mL)/1000 = 1.168 g ≅ 1.17 g.

Ivenika [448]3 years ago
3 0
<h2>Answer:</h2>

<u>The right choice is </u><u>(C) 1.17 grams</u><u> </u>

<h2>Explanation:</h2>

As we know

c = n/V

n = c * V  

n = m/M  

m = c* V * M  

m = 0.1mol/L * 0.2 L * 58.44 g/mol  

m = 1.1688 g ≈ 1.17 g  

So the mass of NaCl needed will be 1.17 grams

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Answer:

a. Molarity= M =2.1x10^{-1}M

b. Molality= m=2.0x10^{-1}m

Explanation:

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In this case, given the information about the aniline, whose molar mass is 93g/mol, one could assume the volume of the solution is just 200 mL (0.200 L) as no volume change is observed when mixing, therefore, the molarity results:

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Answer:

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Explanation:

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