I believe it would be D. Electromagnet. It's been a while since I've done this stuff, tho. Hope this helps!!!! :)
Answer:
In the option(A) moles of HCl left are 0.100 moles which is wrong, making the option incorrect.
Explanation:
![Fe(s) + 2HCl(aq)\rightarrow FeCl_2(aq) + H_2(g) ](https://tex.z-dn.net/?f=Fe%28s%29%20%2B%202HCl%28aq%29%5Crightarrow%20%20FeCl_2%28aq%29%20%2B%20H_2%28g%29%0A)
Moles of HCl = n
Molarity of HCl = 1.0M
Volume of HCl solution = 30.0 mL = 0.030 L (1 mL = 0.001L)
![Moles=Molarity\times Volume (L)](https://tex.z-dn.net/?f=Moles%3DMolarity%5Ctimes%20Volume%20%28L%29)
![n=1.0M\times 0.030 L=0.030 mol](https://tex.z-dn.net/?f=n%3D1.0M%5Ctimes%200.030%20L%3D0.030%20mol)
Moles of Fe = ![\frac{0.56 g}{56 g/mol}=0.01 mol](https://tex.z-dn.net/?f=%5Cfrac%7B0.56%20g%7D%7B56%20g%2Fmol%7D%3D0.01%20mol)
According to recation , 1mol of Fe reacts with 2 mol HCl. Then 0.01 mole of Fe will recat with :
of HCl
This means that HCl uis in excess , hence excessive reagent.
Moles of HCl left unreacted :
= 0.030 mol - 0.020 mol = 0.010 mol
But in the option moles of HCl left are 0.100 moles which is wrong, making the option incorrect.
Answer:
The answer is 2
The maximum number an subshell can have is 2
there are 6 moles of oxygen in Zn(No3)2
Answer:
![{S}^{16}](https://tex.z-dn.net/?f=%20%7BS%7D%5E%7B16%7D%20)
group 16 period 2 of the periodic table
note: that is not the electronic configuration, that is the Bohr model.