1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serggg [28]
2 years ago
10

suppose a 51 kg bungee jumper steps off the royal gorge bridge, in colorado. The bridge is situated 321 m above the arkansas riv

er. the bungee cords spring constant is 32 N/m, the cords relaxed length is 104m and its length is 179m when the jumpers stops falling. what is the total potential energy associated with the jumper at the end of his fall? assume that the bungee cord has negligible mass
Physics
1 answer:
Akimi4 [234]2 years ago
6 0

The total potential energy associated with the jumper at the end of his fall is 90,000 J.

The given parameters;

  • <em>mass of the jumper, m = 51 kg</em>
  • <em>height of the bridge. h  = 321 m</em>
  • <em>spring constant of the cord, k = 32 N/m</em>
  • <em>extension of the cord, x = 179 m - 104 m = 75 m</em>

The total potential energy associated with the jumper at the end of his fall is calculated as follows;

U = ¹/₂kx² + mgΔh

where;

<em>Δh is the change in height after falling </em>

U = ¹/₂(32)(75)²  + (51)(9.8)(0)

U = 90,000 J

Thus, the total potential energy associated with the jumper at the end of his fall is 90,000 J.

Learn more here:brainly.com/question/15731149

You might be interested in
A pendulum of length l=5.0m attached to the ceiling carries a ball of mass 10.0 kg. The ball (a massive bob) is moved from its s
never [62]

Answer:

    Em₀ = 245 J

Explanation:

We can solve this problem with the concepts of energy conservation, we assume that there is no friction with the air.

Initial energy the highest point

        Em₀ = U

        Em₀ = m g h

The height can be found with trigonometry

The length of the pendulum is L and the length for the angle of 60 ° is L ’, therefore the height from the lowest point is

         h = L - L’

         cos θ = L ’/ L

         L ’= L cos θ

          h = L (1 - cos θ)

We replace

         Em₀ = m g L (1- cos θ)

Let's calculate

         Em₀ = 10 9.8 5.0 (1 - cos 60)

         Em₀ = 245 J

3 0
3 years ago
an ice skater applies a horizontal force to a 20.-kilogram block on frictionless, level ice, causing the block to accelerate uni
stiv31 [10]
The only vertical forces are weight and normal force, and they balance since the surface is horizontal. The horizontal forces are the applied force (uppercase F) in the direction the block slides and the frictional force (lowercase f) in the opposite direction.

Apply Newton's 2nd Law in the horizontal direction:
ΣF = ma
F - f = ma
where f = µmg

F - µmg = ma
F = m(a +µg)
F = (20 kg)(1.4 m/s² + 0.28(9.8 m/s²)

F = 83 N
3 0
3 years ago
If earth increase the distance from the sun, what will happen to the period of orbi t(the time it takes to complete one revoluti
Mandarinka [93]

The period of the orbit would increase as well

Explanation:

We can answer this question by applying Kepler's third law, which states that:

"The square of the orbital period of a planet around the Sun is proportional to the cube of the semi-major axis of its orbit"

Mathematically,

\frac{T^2}{a^3}=const.

Where

T is the orbital period

a is the semi-major axis of the orbit

In this problem, the question asks what happens if the distance of the Earth from the Sun increases. Increasing this distance means increasing the semi-major axis of the orbit, a: but as we saw from the previous equation, the orbital period of the Earth is proportional to a, therefore as a increases, T increases as well.

Therefore, the period of the orbit would increase.

Learn more about Kepler's third law:

brainly.com/question/11168300

#LearnwithBrainly

5 0
4 years ago
A Huge water tank is 2m above the ground if the water level on it is 4.9m high and a small opening is there at the bottom then t
lapo4ka [179]

Answer:

The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.

Explanation:

Let assume the existence of a line of current between the water tank and the ground and, hence, the absence of heat and work interactions throughout the system. If water is approximately at rest at water tank and at atmospheric pressure (P_{atm}), then speed of efflux of the non-viscous water is modelled after the Bernoulli's Principle:

P_{1} + \rho\cdot \frac{v_{1}^{2}}{2} + \rho\cdot g \cdot z_{1} = P_{2} + \rho\cdot \frac{v_{2}^{2}}{2} + \rho\cdot g \cdot z_{2}

Where:

P_{1}, P_{2} - Water total pressures inside the tank and at ground level, measured in pascals.

\rho - Water density, measured in kilograms per cubic meter.

g - Gravitational acceleration, measured in meters per square second.

v_{1}, v_{2} - Water speeds inside the tank and at the ground level, measured in meters per second.

z_{1}, z_{2} - Heights of the tank and ground level, measured in meters.

Given that P_{1} = P_{2} = P_{atm}, \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}}, v_{1} = 0\,\frac{m}{s}, z_{1} = 6.9\,m and z_{2} = 4.9\,m, the expression is reduced to this:

\left(9.807\,\frac{m}{s^{2}} \right)\cdot (6.9\,m) = \frac{v_{2}^{2}}{2} + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.9\,m)

And final speed is now calculated after clearing it:

v_{2} = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (6.9\,m-4.9\,m)}

v_{2} \approx 6.263\,\frac{m}{s}

The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.

5 0
4 years ago
An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 481 km from the center of asteroid
mariarad [96]

Explanation:

It is given that, An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 481 km from the center of asteroid Y, along the straight line joining the centers of the asteroids. We need to find the ratio of their masses.

As they are in equilibrium, the force of gravity due to each other is same. So,

\dfrac{Gm_xM}{r^2}=\dfrac{Gm_yM}{r^2}\\\\\dfrac{m_x}{r_x^2}=\dfrac{m_y}{r_y^2}\\\\\dfrac{m_x}{r_x^2}=\dfrac{m_y}{r_y^2}\\\\\dfrac{m_x}{m_y}=(\dfrac{r_x^2}{r_y^2})\\\\\dfrac{m_x}{m_y}=(\dfrac{140^2}{481^2})\\\\\dfrac{m_x}{m_y}=0.0847

So, the ratio of masses X/Y is 0.0847

5 0
3 years ago
Other questions:
  • It takes a person 22 seconds to swim in a straight line from the south end of
    7·1 answer
  • A bodybuilder loads a bar with 550 Newtons (~125 pounds) of weight and pushes the bar over her head 10 times. Each time she lift
    11·2 answers
  • Two spaceships are each traveling in a straight line at 0.95c. The first ship is moving directly toward the Sun. The second ship
    5·1 answer
  • Fluorescent lights tend to emit less of what color?
    10·2 answers
  • Which scientist proposed the idea of studying humans as groups rather than as individuals?
    14·2 answers
  • When a glass rod is rubbed with silk, it becomes positive and the silk becomes negative—yet both attract dust. Does the dust hav
    5·1 answer
  • Your ____ never changes despite what planet you go to
    7·2 answers
  • A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s2 for 10 seconds. During this time, the train
    9·1 answer
  • An electric eel develops a 450 V potential difference between its head and tail. The eel can stun a fish or other prey by using
    10·1 answer
  • A town is considering building a biodiesel power plant that would burn a biomass to generate electricity. Which of the following
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!