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galina1969 [7]
2 years ago
9

If a sealed syringe is plunged into cold water, in which direction will the syringe piston slide? *

Physics
1 answer:
Tamiku [17]2 years ago
5 0

Answer:

a

Explanation:

can you help me with my question According to the narrator in Paragraph 3 of "The Celebrated Jumping Frog of Calaveras County," Simon Wheeler's tone throughout his entire tale was A earnest and sincere, B. excited and pressing, C. sad and melancholy,

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What are some other examples of a force acting on an object without<br> touching it?
a_sh-v [17]
An example would be gravity
8 0
3 years ago
An elevator accelerates upward at 2.0 m/s?,
amm1812

Answer:

Force the floor exerts on the  passenger is 833 N.

Explanation:

  • Weight of passenger (F_{g}) = mg = 85 × 9.8 N = 833 N
  • Force the floor exerts on the  passenger (F_{N}) = ?
  • For the elevator with the speed as 2.0 m/s the net force is zero, it means that the force is balanced.

                                       i.e. F_{N} = - F_{g} = -mg = 833 N

                                       hence  F_{N} is 833 N

  • If the lift was not at a constant speed i.e. if it had acceleration (m/s^{2})  then the case would be different.

4 0
3 years ago
In the Hydrogen atom, the energy spacing between the is 4.07 x 101 J (Joules). When an is the frequency of the photons emitted?
agasfer [191]

Answer:

The frequency of the photon is 3.069\times10^{14}\ Hz.

Explanation:

Given that,

Energy E=4.07\times10^{-19}\ J

We need to calculate the energy

Using relation of energy

E_{4}-E_{2}=\Delta E

Where, \Delta E =  energy spacing

4h\nu-2h\nu=4.07\times10^{-19}

\nu=\dfrac{4.07\times10^{-19}}{2h}

Put the value of h into the formula

\nu=\dfrac{4.07\times10^{-19}}{2\times6.63\times10^{-34}}

\nu=3.069\times10^{14}\ Hz

Hence, The frequency of the photon is 3.069\times10^{14}\ Hz.

4 0
3 years ago
If we have less power, we most likely have
katrin [286]
<span>the same amount of work being done over a longer period of time.</span>
3 0
2 years ago
Read 2 more answers
A source charge generates an electric field of 4286 N/C at a distance of 2. 5 m. What is the magnitude of the source charge? (Us
svp [43]

The magnitude of the source charge is 3 μC which generates 4286 N/C of the electric field. Option B is correct.

What does Gauss Law state?

It states that the electric flux across any closed surface is directly proportional to the net electric charge enclosed by the surface.

Q = \dfrac {ER^2}k

Where,

E = electric force = 4286 N/C

k = Coulomb constant = 8.99 \times  10^9 \rm\ N m ^2 /C ^2

Q\\&#10;     = charges = ?

r = distance of separation = 2.5 m

Put the values in the formula,

Q  = \dfrac {4286\times  2.5 ^2}{8.99 \times  10^9 }\\\\&#10;Q  = 3\rm \  \mu C

Therefore, the magnitude of the source charge is 3 μC.

Learn more about Gauss's law:

brainly.com/question/1249602

8 0
2 years ago
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