Question

An air gun fires 2 gram pellets at 60 m/s at a 45 gram golfball initially at rest. The pellets rebound at a speed 40 m/s and are fired at a rate of 4 per second, How much momentum is delivered to the golf ball each second in kg*m/s

Answer 1

Answer:

0.16 kgm/s

Explanation:

$m_1$ = Mass of pellet = 2 g

$m_2$ = Mass of golf ball = 45 g

$u_1$ = Initial Velocity of pellet  = 60 m/s

$u_2$ = Initial Velocity of golf ball = 0 m/s

$v_1$ = Final Velocity of pellet = 40 m/s

$v_2$ = Final Velocity of golf ball

In this system the linear momentum is conserved

$m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow m_2v_2=m_1u_1+m_2u_2-m_1v_1\\\Rightarrow m_2v_2=0.002\times 60+0-0.002\times 40\\\Rightarrow m_2v_2=0.04$

As the golf ball is being shot 4 times every second the momentum delivered to the golf ball each second is $4\times 0.04=0.16\ kgm/s$