Answer:
The car requires 192 feet to stop from a speed of 48 miles per hour on the same road
Step-by-step explanation:
- Direct proportion means that two quantities increase or decrease in the same ratio
- If y is directly proportional to x (y ∝ x) , then
<em>OR</em> y = k x, where k is the constant of proportionality
∵ The stopping distance d of an automobile is directly
proportional to the square of its speed s
- That means d ∝ s²
∴ 
∵ A car requires 75 feet to stop from a speed of 30 miles per hour
∴ d = 75 feet
∴ s = 30 miles/hour
- Change the mile to feet
∵ 1 mile = 5280 feet
∴ 30 miles/hour = 30 × 5280 = 158400 feet/hour
∵ The car require to stop from a speed of 48 miles per hour
on the same road
- Change the mile to feet
∴ 48 miles/hour = 48 × 5280 = 253440 feet/hour
∵
- Substitute the values of 
by 75 feet, 
by 158400 feet/hour
and 
by 253440 feet/hour
∴ 
∴ 
- By using cross multiplication
∴ 25 × 
= 75 × 64
- Divide both sides by 25
∴ = 192 feet
The car requires 192 feet to stop from a speed of 48 miles per hour on the same road
I do not know my friend . Answer for this
Answer:
The equation that can be used to solve for a is 1 = a(0=1)²-3.
Explanation:
In this case, I would model the parabola in vertex form. Vertex form is y = a(x-h)²+k, where (h,k) is the vertex of the parabola. Using the information from the question, we can plug in values to get 1 = a(0+1)²-3. (This could be simplified as 1 = a(1)²-3 ⇒ 1 = a-3 ⇒ a = 4, but we are only interested in finding the equation that can solve for a.)
Answer:
1152 diapers are needed
Step-by-step explanation:
2 dozen babies is equall to 24 babies
-(1 dozen is 12 babies)
If 24 babies need a package of diapers which includes 48 diapers, we need to multiply 24x48 which equals 1152 diapers
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:
P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:
P = 0.59
