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mafiozo [28]
3 years ago
10

Equilateral triangle ABC has a perimeter of 96 milimeters. A perpendicular bisector is drawn from angle A to side seg.BC at poin

t M. What is the length of seg.MC?
A) 16mm
B)24mm
C)32mm
D)48mm
Mathematics
2 answers:
Sidana [21]3 years ago
6 0
In an equilateral triangle the perpendicular drawn from one vertex to its opposite side bisects the opposite sides in 2 equal parts.
Moreover the side of this equilateral triangle =96/3 =32 mm

Hence MC =32/2 16 mm
jonny [76]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answer:

y=(x-3)^2-6

Step-by-step explanation:

y=x^2-6x+3

This is written in the standard form of a quadratic function:

y=ax^2+bx+c

where:

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  • bx → linear term
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You need to convert this to vertex form:

y=a(x-h)^2+k

where:

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To find the vertex form, you need to find the vertex. For this, use the equation for axis of symmetry, since this line passes through the vertex:

x=-\frac{b}{2a}

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a=1\\\\b=-6\\\\c=3

Insert the known values into the equation:

x=-\frac{(-6)}{2(1)}

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y=3^2-6(3)+3

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y=9-18+3\\\\y=-9+3\\\\y=-6

The value of y is -6 (3,-6). Insert these values into the vertex form:

(3_{h},-6_{k})\\\\y=a(x-3)^2+(-6)

Insert the value of a and simplify:

y=(x-3)^2-6

:Done

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Step-by-step explanation:

from the question:R=x^2/y

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