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3 years ago

8

PLEASE HELP ME

1 answer:

lesya [120]3 years ago

6 0

Answer:

football

Explanation:

it is played on zig-zay way/form

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The normal boiling point of water is 100.0 °c and its molar enthalpy of vaporization is 40.67 kj/mol. what is the change in entr

SashulF [63]

ΔS= nΔHvap/T,

Where, ΔS = Change in entropy, n = moles of water = 39.3/18 = 2.188 moles, ΔHvap = 40.67kJ/mol = 40670 J/mol, T = Temperature (K) = 100+272.15 = 373.15 K

Therefore,
ΔS = (2.188*40670)/373.15 = 237.96 J/K

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3 years ago

An instrument is defective for all of the following conditions EXCEPT:_______

NARA [144]

Answer:

I believe its C

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4 years ago

A brick lands 10.1 m from the base of a building. If it was given an initial velocity of 8.6 m/s [61º above the horizontal], how

Montano1993 [528]

<h2>Answer: 10.52m</h2><h2 />

First, we have to establish the <u>reference system</u>. Let's assume that the building is on the negative y-axis and that the brick was thrown at the origin (see figure attached).

According to this, the initial velocity $V_{o}$ has two components, because the brick was thrown at an angle $\alpha=61\º$ :

$V_{ox}=V_{o}cos\alpha$ (1)

$V_{ox}=8.6\frac{m}{s}cos(61\º)=4.169\frac{m}{s}$ (2)

$V_{oy}=V_{o}sin\alpha$ (3)

$V_{oy}=8.6\frac{m}{s}sin(61\º)=7.521\frac{m}{s}$ (4)

As this is a projectile motion, we have two principal equations related:

<h2>In the x-axis: </h2>

$X=V_{ox}.t$ (5)

Where:

$X=10.1m$ is the distance where the brick landed

$t$ is the time in seconds

If we already know $X$ and $V_{ox}$ , we have to find the time (we will need it for the following equation):

$t= \frac{X}{ V_{ox}}$ (6)

$t=2.42s$ (7)

<h2>In the y-axis: </h2>

$-y=V_{oy}.t+\frac{1}{2}g.t^{2}$ (8)

Where:

$y$ is the height of the building (<u>in this case it has a negative sign because of the reference system we chose)</u>

$g=-9.8\frac{m}{s^{2}}$ is the acceleration due gravity

Substituting the known values, including the time we found on equation (7) in equation (8), we will find the height of the building:

$-y=(7.521\frac{m}{s})(2.42s)+\frac{1}{2}(-9.8\frac{m}{s^{2}}).(2.42s)^{2}$ (9)

$-y=-10.52m$ (10)

Multiplying by -1 each side of the equation:

$y=10.52m$ >>>>This is the height of the building

3 0

3 years ago

When work is done on an object , the results is an increase in its what

Ksju [112]

Answer:Im guessing Mechanical Energy

Explanation:

We are learning that work and energy work hand in hand so im completely guessing this

5 0

3 years ago

Read 2 more answers

You hold a small metal ball of mass a height above the floor. You let go, and the ball falls to the floor. Choose the origin of

baherus [9]

Answer:

yᵢ = h

vᵢᵧ = 0

Explanation:

Let initial velocity = u

final velocity = v

height = h

acceleration due to gravity = g

Therefore fro equation of motion,

$v^{2}=u^{2}+2gh$

Here initial velocity is zero.

Hence, $v^{2}=2gh$

$v = \sqrt{2gh}$

but since it points downward and you positive is taken in the up direction

$v = -\sqrt{2gh}$

5 0

4 years ago