Answer:
b I'm sorry if its not true
Answer:

Explanation:
Hello there!
In this case, since this imaginary gas can be modelled as an ideal gas, we can write:

Which can be written in terms of density and molar mass as shown below:

Thus, by computing the pressure in atmospheres, the resulting density would be:

Best regards!
Answer:
1.18 moles of gas
Explanation:
3.00 moles of gas are pumped into a 1.00L rigid container with a pressure of 1.98 atm. The gas is released from the container until the pressure is 0.78 atm, how many moles of gas remain in the container?
for the sealed rigid container, the pressure is directly proportional to the amount of gas
3.00moles/1.98 atm = ? moles/0.78 atm
? = 3.00 X 0.78/1.98 =1.18 moles of gas
Sorry I honestly have no idea I just want my points