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lilavasa [31]
3 years ago
12

How many grams of magnesium oxide forms when 8.0g of magnesium are burned?

Chemistry
1 answer:
AfilCa [17]3 years ago
7 0
Magnesium burns with oxygen to give magnesium oxide based on the following reaction:
2M<span>g</span>+<span>O<span>2 </span></span>........> 2Mg<span>O<span>(s)</span></span>+<span>energy
</span>From the periodic table:
molecular mass of magnesium = 24.3 grams
molecular mass of oxygen = 16 grams

From the reaction:
2 x 24.3 = 48.6 grams of magnesium are required to produce 2(24.3+16) = 80.6 grams of magnesium oxide.
We can know the amount of magnesium oxide produced from 8 grams of magnesium by simply doing cross multiplication as follows:
amount of magnesium oxide = (8 x 80.6) / 48.6 = 13.267 grams

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Answer:

Δ S = 26.2 J/K

Explanation:

The change in entropy can be calculated from the formula  -

Δ S = m Cp ln ( T₂ / T₁ )

Where ,

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T₂ = final temperature  10.0°C + 273 = 283 K

T₁ = initial temperature ,  40.0°C + 273 = 313 K

Applying the above formula ,

The change in entropy is calculated as ,

ΔS = m Cp ln ( T₂ / T₁ )  = (2.00 )( 130 ) ln( 283 K / 313 K )

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What factors do not affect nuclear reactions, but do affect chemical reaction
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