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Simora [160]
3 years ago
10

27/13Al+4/2He >>>> 30/15P+

Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
5 0

Answer

Explanation:

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

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A sample of the mineral hematite Iron (III) oxide has a mass of 12.4g. How many moles of the mineral are present?
8090 [49]

Thus problem is providing us with the mass of iron (III) oxide as 12.4 g so the moles are required and found to be 0.0776 mol after the calculations:

<h3>Mole-mass relationships:</h3>

In chemistry, we use mole-mass relationships in order to calculate grams from moles and vice versa. In this case, since we are given the mass of iron (III) oxide as 12.4 g one can calculate the moles by firstly quantifying its molar mass:

Fe_2O_3\rightarrow 2*55.85 g/mol+3*16.00 g/mol=159.7g/mol

Then, we prepare a conversion factor in order to cancel out the grams and thus, get moles:

12.4gFe_2O_3*\frac{1molFe_2O_3}{159.7gFe_2O_3} \\\\=0.0776molFe_2O_3

Learn more about mole-mass relationships: brainly.com/question/18311376

8 0
2 years ago
In a chemical equation, changing the subscript in a chemical formula for a substance changes what aspect?
Citrus2011 [14]
The subscript in a chemical formula is the number written next to the element at the bottom part. For example, the chemical formula of water is H₂O. The subscript of H is 2, while the subscript of O is 1. The subscript represents the number of a certain element in one particle of the compound. So, if you change the subscript, you also change the number of a certain element per compound. In other words, you change the ratio.
4 0
3 years ago
Read 2 more answers
How many chlorine atoms are found in 8.3 moles of chlorine?
erik [133]

Answer:

5*10²⁴ chlorine atoms are found in 8.3 moles of chlorine.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 1 mole of the compound contains 6.023 * 10²³ atoms, 8.3 moles of the compound how many atoms does it have?

amount of atoms=\frac{8.3 moles*6.023*10^{23}atoms }{1 mole}

amount of atoms≅ 5*10²⁴ atoms

<u><em>5*10²⁴ chlorine atoms are found in 8.3 moles of chlorine.</em></u>

4 0
3 years ago
Which of the following actions would cause the volume of the chamber below to increase to 36.0 L?
Orlov [11]

Answer:

Option C. Triple the number of moles

Explanation:

From the ideal gas equation:

PV = nRT

Where:

P is the pressure

V is the volume

n is the number of mole

R is the gas constant

T is the absolute temperature.

Making V the subject of the above equation, we have:

PV = nRT

Divide both side by P

V = nRT / P

Thus, we can say that the volume (V) is directly proportional to both the number of mole (n) and absolute temperature (T) and inversely proportional to the pressure (P). This implies that and increase in either the number of mole, the absolute temperature and a decrease in the presence will cause the volume to increase.

Thus, the correct option is option C triple the number of moles. This can further be seen as illustrated below:

Initial volume (V1) = 12 L

Initial mole (n1) = 0.5 mole

Final mole (n2) = triple the initial mole = 3 × 0.5 = 1.5 mole

Final volume (V2) =?

From:

V = nRT / P, keeping T and P constant, we have:

V1/n1 = V2/n2

12/0.5 = V2/1.5

24 = V2/1.5

Cross multiply

V2 = 24 × 1.5

V2 = 36 L.

Thus Option C gives the correct answer to the question.

5 0
3 years ago
If nitrogen and hydrogen combine in a combustion reaction, what would the product of the reaction be?
kow [346]

Co2

Explanation:

CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)

4 0
3 years ago
Read 2 more answers
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