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aleksandrvk [35]
3 years ago
8

What components must be built to create a hydroelectric power?

Chemistry
1 answer:
mariarad [96]3 years ago
4 0
The answer is C hope this help's.
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Ni-cad (nickel–cadmium) batteries have a slightly lower cell potential than the common alkaline value of 1.5 v normally used in
Lorico [155]
The half-reaction are:

Cd ---> Cd(OH)₂
The oxidation number of Cd changed from 0 to +2. So, the number of mol electron transferred here is 2.

NiO(OH) --> Ni(OH)₂
The oxidation number of Cd changed from +3 to +2. So, the number of mol electron transferred here is 1.

Now, the greatest common factor would be 2. So, we use n=2 for the formula for ΔG°. F is Faraday's constant equal to 96,485 J/mol e.

ΔG° = nFE° = (2)(96,485)(1.5) =<em> 289,455 J</em>


6 0
2 years ago
The reaction of nitrogen dioxide with fluorine
andrew-mc [135]

Answer:

Rate = 0.001615 Ms-1

Explanation:

2 NO2 + F2 --> 2 NO2F

The reaction is first order with respect to NO2 and also first order with respect to F2.

The rate law is given as;

Rate = k [NO2] [ F2]

k = 1.58E-4 M-1s-1

[NO2] = 2.84 M

[F2] = 3.60 M

Rate = ?

Inserting the values into the equation, we have;

Rate = 1.58E-4 * 2.84 * 3.60

Rate = 0.001615 Ms-1

4 0
3 years ago
Which element is in the same family as Chlorine (Cl) and Fluorine (F)?
ValentinkaMS [17]

Answer/Explanation:

Chlorine and Fluorine are in the Halogen family. The elements in the Halogen family are:

Fluorine (F)

Chlorine (Cl)

Bromine (Br)

Iodine (I)

Astatine (At)

Tennessine (Ts)

Hydrogen (H) is a nonmetal

Oxygen (O) is a nonmetal

Lithium (Li) is an alkaline metal.

8 0
3 years ago
Read 2 more answers
The three naturally occurring isotopes of potassium are 39K, 38.963707u; 40K, 39.963999u; and 41K.The percent natural abundances
sweet-ann [11.9K]

Answer:

The isotopic mass of 41K is 40.9574 amu

Explanation:

Step 1: Data given

The isotopes are:  

39K with an isotopic mass of 38.963707u and natural abundance of 93.2581%

40K with an isotopic mass of 39.963999u

41K wit natural abundance of 6.7302 %

Average atomic mass =39.098 amu  

Step 2: Calculate natural abundance of 40 K

100 % - 93.2581 % - 6.7302 %

100 % = 0.0117 %

Step 3: Calculate isotopic mass of 41K

39.098 = 38.963707 * 0.932581 + 39.963999 * 0.000117 + X * 0.067302

39.098 = 36.33681 + 0.0046758 +  X * 2.067302

X = 40.9574 amu

The isotopic mass of 41K is 40.9574 amu

8 0
3 years ago
A. Moles of O2, needed to produce 7 moles of product?
lidiya [134]

Answer:

b

b.

Explanation:

4 0
2 years ago
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