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2 years ago

Correct will get brainliest.

Mathematics

2 answers:

AVprozaik [17]2 years ago

8 0

D and e because I did it E 2020:)

dimulka [17.4K]2 years ago

6 0

Answer:

D and E

Step-by-step explanation:

He divides the number line into 6 equal parts. Meaning that 6/6 would be the whole, and the denominator would be 6, or a simplified version of that.

so you got the generic 1/6, 2/6, 3/6, 4/6 and 5/6, which is D

but E is the simplified version of the previous one

2/6 simplifies into 1/3

4/6 simplifies ino 2/3

So technically E is correct as well, just a simplified version of D, thus your answer choices being D and E.

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What is the value of pie and how can I round it to the nearest tenth

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5 0

3 years ago

Read 2 more answers

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jok3333 [9.3K]

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6 0

3 years ago

Adam uses coconut milk for the dessert.

dmitriy555 [2]

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4 0

3 years ago

2/3 of a class are girls what is the ratio of girls to boys in class answer simplest form

77julia77 [94]

Answer:

2:1

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

An airplane is preparing to land at an airport. It is 44,8000 feet above the ground and is descending at the rate of 3,100 feet

Marina86 [1]

Answer:

Time: 8 minutes

Altitude: 20000ft

Method 1 is easiest

Method 3 is easiest

Step-by-step explanation:

Given

Airplane 1:

$Height = 44800 ft$

$Descending\ Rate = 3100ft/min$

Airplane 2:

$Ascending\ Rate = 2500ft/min$

Required

Determine when both planes would be at the same altitude?

Let the minute be represented by m

For Airplane 1, Its altitude at any height h is:

$Airplane\ 1 = Height - Descending\ Rate * m$

It is minus (-) because the airplane is descending

$Airplane\ 1 = 44800 - 3100 * m$

$Airplane\ 1 = 44800 - 3100m$

For Airplane 2, Its altitude at any height h is:

$Airplane\ 2 = Ascending\ Rate * m$

$Airplane\ 2 = 2500 * m$

$Airplane\ 2 = 2500m$

Method 1:

For both heights to be equal, we have that:

$Airplane\ 1 = Airplane\ 2$

This gives:

$44800 - 3100m = 2500m$

Collect Like Terms

$44800 = 2500m + 3100m$

$44800 = 5600m$

$5600m = 44800$

$m = 44800/5600$

$m = 8\ min$

Hence, the time they will be at the same altitude is 8 minutes

Substitute 8 for m in

$Airplane\ 2 = 2500m$

$Airplane\ 2 = 2500 * 8$

$Airplane\ 2 = 20000\ ft$

Hence, they will be at the same altitude at 20000ft

Method 2:

We have that:

$Airplane\ 1 = 44800 - 3100m$

$Airplane\ 2 = 2500m$

Since they are to be at the same altitude, then

The difference in their altitude must be 0

i.e.

$Airplane\ 1 - Airplane\ 2 = 0$

This gives

$44800 - 3100m - 2500m = 0$

$44800 - 5600m = 0$

Collect Like Terms

$5600m = 44800$

$m = 44800/5600$

$m = 8\ min$

Substitute 8 for m in

$Airplane\ 1 = 44800 - 3100m$

$Airplane\ 1 = 44800 - 3100 * 8$

$Airplane\ 1 = 44800 - 24800$

$Airplane\ 1 = 20000\ ft$

Method 3:

We have that:

$Airplane\ 1 = 44800 - 3100m$

$Airplane\ 2 = 2500m$

Since they are to be at the same altitude, then

The ratio of their altitudes must be 1

i.e.

$\frac{Airplane\ 1}{Airplane\ 2} = 1$

$\frac{44800 - 3100m}{2500m} = 1$

Cross Multiply

$44800 - 3100m = 1 * 2500m$

$44800 - 3100m = 2500m$

Collect Like Terms

$44800 = 2500m + 3100m$

$44800 = 5600m$

$5600m = 44800$

$m = 44800/5600$

$m = 8\ min$

Substitute 8 for m in

$Airplane\ 1 = 44800 - 3100m$

$Airplane\ 1 = 44800 - 3100 * 8$

$Airplane\ 1 = 44800 - 24800$

$Airplane\ 1 = 20000\ ft$

Hence;

Their altitudes must be 20000ft

Though the three methods applied uses the same logic at some point, the first method applied is still the easiest and it is a straight forward method that could be applied in solving the question.

Method 3 is the most difficult.

7 0

3 years ago