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Alenkasestr [34]
3 years ago
11

Please answer this question correctly

Mathematics
1 answer:
hoa [83]3 years ago
4 0
The answer is two because it goes up two times every time
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Sumalee won 40 super bouncy balls playing horseshoes at her school's game
anzhelika [568]

let x represent how many friends Sumalee has.

40-2(x)=8

40 original balls - 2 to each friend = 8 balls left

3 0
3 years ago
Read 2 more answers
Suizi bought 5 packages of M&M and each package contained 18 candy pieces. She opened the frist package and counted 4 green
masha68 [24]
<h3>There are fewer than 14 green pieces in all 5 packages. </h3>

Step-by-step explanation:

Here, the given question is incomplete.

Suzi bought 5 packages of M&M's, and each package contained 18 candy pieces. She opened the first package and counted 4 green pieces. She then counted 3 green pieces in the second package. Which statement about the candy pieces in the remaining packages is best supported by this information?

A. There are fewer than 14 green pieces in all 5 packages.

B. There are between 15 and 20 green pieces in all 5 packages.

C. There are at least 25 green pieces but no more than 50 in all 5 packages. D. There are more than 50 green pieces in all 5 packages.

Now, here given:

The number of packages of M & M purchased  = 5 packets

The number of candies in each packet = 18

The number of green candies in first pack  = 4

The number of green candies in second pack  = 3

Now as we can see the number of green candies in <u>decreasing by 1</u><u> </u>in number as we open more packets.

So, according to this pattern:

The number of green candies in third pack  = 2

The number of green candies in fourth pack  = 1

And the fifth pack will have NO green candies.

So, the total number of green candies in all 5 packets combined  

=  4  + 3+ 2 + 1 + 0

=  10 green candies

⇒  There are fewer than 14 green pieces in all 5 packages.

5 0
3 years ago
An engineering school reports that 52% of its students are male (M), 33% of its students are between the ages of 18 and 20 (A),
weeeeeb [17]

Answer:

42%

Step-by-step explanation:

Given: P(M) = 0.52, P(A) = 0.33, and P(M and A) = 0.27.

Find: P(not M and not A).

P(not M and not A) = 1 − P(M or A)

P(not M and not A) = 1 − (P(M) + P(A) − P(M and A))

P(not M and not A) = 1 − (0.52 + 0.33 − 0.27)

P(not M and not A) = 1 − 0.58

P(not M and not A) = 0.42

5 0
3 years ago
3x(×-4)-5(x+2)=2-(x+24)
just olya [345]
The zeros to the problem are:
x = .90283246
x = 4.4305009
4 0
3 years ago
HELP ME!! WILL MARK BRAINLIEST DUE TODAY!!<br> there are two parts to it !
Varvara68 [4.7K]

Answer:

Part A: A      

Step-by-step explanation:

Part B: -6 - x - 0

4 0
3 years ago
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