Answer:3.5 moles * 6.02 X 10^23 particles/mole * 2 H atoms/particle of H2 = 42.14 X 10^^23 atoms
Explanation:
Answer:
53.2
Explanation:
The balanced reaction is:
2Fe(s) + 3O₂(g) → Fe₂O₃
It means that 3 moles of oxygen form 1 mol of iron(III) oxide. The molar masses are: Fe = 55.8 g/mol and O = 16 g/mol. So
O₂ = 2x 16 = 32 g/mol
Fe₂O₃ = 2x55.8 + 3x16 = 159.6 g/mol
So, 32 g of O₂ corresponds to 1 mol of O₂. The stoichiometry calculus must be (always in moles):
3 mol of O₂ ------------------------ 1 mol of Fe₂O₃
1 mol of O₂ ------------------------ x
By a direct simple three rule:
3x = 1
x = 1/3 mol of Fe₂O₃
The mass is the molar mass multiplied by the number of moles, so:
m = 159.6x (1/3)
m = 53.2 g iron (III) oxide.
Chlorofluorocarbons and other halogenated ozone depleting substances are mainly responsible for man made chemical ozone depletion.
Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-
Ca(OH)</span>₂ is <span>strong Bases</span><span>
</span>Therefore, the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]
pOH = - log [ <span>5 x 10⁻⁴ ]
pOH = 3.30
pH + pOH = 14
pH + 3.30 = 14
pH = 14 - 3.30
pH = 10.7
hope this helps!</span>