calculate the number of coulombs of positive charge in 250cm 3 of (neutral) water. (hint: a hydrogen atom contains one proton; a
1 answer:
Number of coulombs of positive charge in 250cm^3 water is 1.3×10^7 C
The volume of 250 cm^3 corresponds to a mass of 250 g since the density of water is 1.0 g/cm^3
This mass corresponds to 250/18 = 14 moles since the molar mass of water is 18. There are ten proton (each with charge q = +e) in each molecule of So,
Q = 14NA q =14(6.02×10^23)(10)(1.60×10^−19C) = 1.3×10^7 C.
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Answer :
(A) The number of moles of ions per liter is, 0.1 moles/L
(B) The number of molecules of ion is,
(C) The pH of the solution will be, 4
<u>Solution for part A :</u>
First we have to calculate the pOH of the solution.
As we know that,
Now we have to calculate the moles of ion per liter.
<u>Solution for part B :</u>
First we have to calculate the ion concentration.
Now we have to calculate the number of molecules of ion
As, 1 mole contains number of molecules of
ion
So, moles contains
number of molecules of
ion
<u>Solution for part C :</u>