Question

Determine the pH of a 5x10^-4 M solution of Ca(OH)2

Answer 1

Ca(OH)₂ ==> Ca²⁺ + 2 OH-   

Ca(OH)₂ is strong Bases

Therefore,  the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻.

pOH = - log[ OH⁻]

pOH = - log [ 5 x 10⁻⁴ ]

pOH = 3.30

pH + pOH = 14

pH + 3.30 = 14

pH = 14 - 3.30

pH = 10.7

hope this helps!