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scoundrel [369]
2 years ago
8

How many atoms are in 0.560 moles of iron?

Chemistry
1 answer:
Vinvika [58]2 years ago
8 0

Answer:

3.37288*10^23 atoms

Explanation:

3.37288*10^23 atoms

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10 POINTS
Snowcat [4.5K]
E=hc/λ =6.626×10^-34×3 ×10^8 / 3×10^7 × 10^-9 = 6.626×10 ^-24J.
7 0
3 years ago
Repulsion of electrons within two interacting molecules produces changes in electron distribution. This change in electron distr
ycow [4]

Answer:

D

Explanation:

This explains how two noble gases molecules can have an attractive force between them.

This force is called as van dar Waals forces.

It plays a fundamental role in fields in as diverse as supramolecular chemistry structural biology .

If no other forces are present, the point at which the force becomes repulsive rather than attractive as two atoms near one another is called the van der Waals contact distance. This results from the electron clouds of two atoms unfavorably coming into contact.[1] It can be shown that van der Waals forces are of the same origin as the Casimir effect, arising from quantum interactions with the zero-point field.[2] The resulting van der Waals forces can be attractive or repulsive.[3] It is also sometimes used loosely as a synonym for the totality of intermolecular forces.[4] The term includes the force between permanent dipoles (Keesom force), the force between a permanent dipole and a corresponding induced dipole (Debye force), and the force between instantaneously induced dipoles

6 0
2 years ago
Which is smaller 25 mm or 25cm
umka21 [38]

Answer:

25 mm is smaller.

5 0
3 years ago
What is the final concentration if a 50.0 mL sample of a 15% H2SO4 solution is added to water to give a final volume of 250 mL?
Anna007 [38]

Answer:

The answer to your question is 3% H2SO4 solution

Explanation:

Data

Concentration 2 = C₂ = ?

Concentration 1 = C₁ = 15 %

Volume 1 = V₁ = 50 ml

Volume 2 = V₂ = 250 ml

Formula

             C₁V₁  = C₂V₂

Solve for C₂

             C₂ = C₁V₁ / V₂

Substitution

             C₂ = (15)(50) / 250

Simplification and result

             C₂  = 3 %

4 0
3 years ago
A chiral amine A having the R configuration undergoes Hofmann elimination to form an alkene B as the major product. B is oxidati
Free_Kalibri [48]

Answer:

The Structure of "B" is alkene.

Explanation:

The compound "A" having R- configuration  and undergoes Hofmann elimination to form an alkene.

The compound "B" on oxidatively cleaving with ozone followed by dimethyl sulfide forms CH_{2}=S and CH_{3}CH_{2}CH_{2}CHO

The structure of "A" and"B" is as follows.

3 0
3 years ago
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