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scoundrel [369]
2 years ago
8

How many atoms are in 0.560 moles of iron?

Chemistry
1 answer:
Vinvika [58]2 years ago
8 0

Answer:

3.37288*10^23 atoms

Explanation:

3.37288*10^23 atoms

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What is magnesium used for in its pure form
Sloan [31]

Answer: The pure metal has low structural strength, magnesium is mainly  used in the form of alloys- principally with 10% or less of aluminum, zinc, and manganese- to improve it's hardness, tensile strength, and ability to be cast, welded, and machined.

I hope this really helps you!!! :) And Have a fantastic day!!!

 

6 0
4 years ago
One way to ensure that scientific claims are valid is to analyze who is presenting the information: only trust information prese
Marina86 [1]

False

Explanation:

The best way to ensure scientific claims are valid is to subject them to various tests. Scientific claims has nothing to do with the body presenting them. Claims are authenticated following due scientific process.

  • Scientific method provides a way of ascertaining the validity of an assumption.
  • If the claims is not supported by the body of evidence obtained, then the claim has to be modified or refuted.
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8 0
3 years ago
Read 2 more answers
Quick electron emissions are called
vivado [14]

Answer:

<u>Beta</u><u> </u><u>decay</u>

Quick electron emissions are called <u>beta</u><u> </u><u>decay</u>

<em>Hope</em><em> this</em><em> helps</em>

5 0
3 years ago
Calculate ΔrG∘ at 298 K for the following reactions.CO(g)+H2O(g)→H2(g)+CO2(g)2-Predict the effect on ΔrG∘ of lowering the temper
KonstantinChe [14]

Answer:

1) ΔG°r(298 K) = - 28.619 KJ/mol

2) ΔG°r will decrease with decreasing temperature

Explanation:

  • CO(g) + H2O(g) → H2(g) + CO2(g)

1) ΔG°r = ∑νiΔG°f,i

⇒ ΔG°r(298 K) = ΔG°CO2(g) + ΔG°H2(g) - ΔG°H2O(g) - ΔG°CO(g)

from literature, T = 298 K:

∴ ΔG°CO2(g) = - 394.359 KJ/mol

∴ ΔG°CO(g) = - 137.152 KJ/mol

∴ ΔG°H2(g) = 0 KJ/mol........pure substance

∴ ΔG°H2O(g) = - 228.588 KJ/mol

⇒ ΔG°r(298 K) = - 394.359 KJ/mol + 0 KJ/mol - ( - 228.588 KJ/mol ) - ( - 137.152 KJ7mol )

⇒ ΔG°r(298 K) = - 28.619 KJ/mol

2) K = e∧(-ΔG°/RT)

∴ R = 8.314 E-3 KJ/K.mol

∴ T = 298 K

⇒ K = e∧(-28.619/(8.314 E-3)(298) = 9.624 E-6

⇒ ΔG°r = - RTLnK

If T (↓) ⇒ ΔG°r (↓)

assuming T = 200 K

⇒ ΔG°r(200 K) = - (8.314 E-3)(200)Ln(9.624E-3)

⇒ ΔG°r (200K) = - 19.207 KJ/mol < ΔG°r(298 K) = - 28.619 KJ/mol

6 0
3 years ago
1. At what temperature dose water freeze
Rus_ich [418]

Answer:

1. water will freeze at a temperature below 32 degrees fahrenheit 0 degree celsius.

2. Ice will melt at a temperature above 32 degrees fahrenheit 0 degrees celsius.

3. water boils at 212 degrees fahrenheit or 100 degrees celsius.

8 0
3 years ago
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