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scoundrel [369]
2 years ago
8

How many atoms are in 0.560 moles of iron?

Chemistry
1 answer:
Vinvika [58]2 years ago
8 0

Answer:

3.37288*10^23 atoms

Explanation:

3.37288*10^23 atoms

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(CH3)2-CH-CH2-O(CH3)3IUPAC NAME
bazaltina [42]

Answer:

1-(tert-butoxy)-2-methylpropane

Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.

Explanation:

<em>Structural formula is attached</em>

IUPAC naming rules

1. start numbering the chain from the functional group. In this compound we        start from oxygen side.

2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.

3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.

4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane

5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane

3 0
4 years ago
A sample of iron contains 2.806 x 1024 atoms of iron (Fe). How many moles of iron are in the sample?
xxMikexx [17]

Answer:

Approx. 20 moles of iron.

Explanation:

There are approx. 6.022 x 10.23 iron atoms per mole of iron. In this quantity, The number of iron atoms has a mass of

55.85 ⋅ g.

4 0
2 years ago
Explain how paper chromatography could be used to separate a mixture of different coloured inks
GuDViN [60]

Answer:

Chromatography is a method of separation of materials from a mixture. Paper chromatography is a technique of separation where, paper used as a stationary phase and solvent used to separate the sample used as a mobile phase. The sample is applied over the paper in small quantity. The components of the sample separates in a chromatographic paper due to the movement of solvent. The components of the sample moves with the solvent.

Paper chromatography is a useful technique for ink analysis. Ink consists of several dyes, which can be separated individually. When the ink is exposed to certain solvent mixtures the dyes of the ink dissolves in the mixture. Each ink components acquire distinct distance according to the retention factor. Some inks are water soluble, so the solvent used for separation should be water. Inks which are not water soluble are soluble in other solvents like alcohol.

3 0
3 years ago
What are the gas laws? (Include Boyle's law, charles's law, gay lussac's law, an avogadro's law) Could someone please summarize
Rina8888 [55]

Answer:

Boyle's Law: When the pressure of a gas increases, the volume of the gas will decrease as long as the temperature and amount of gas are constant.

So basically pressure is inversely proportional to Volume, when one increases, the other decreases, vice versa.

Equation: P_{1} V_{1} = P_{2} V_{2}

Charles Law: When the temperature of a gas increases, the volume of a gas will also increase if the pressure and amount of gas are constant.

So basically Temperature and volume are directly proportional.

Equation: \frac{V_{1}}{T_{1}} = \frac{V_{2} }{T_{2} }

Gay Lussac's Law: When the temperature of a gas increases, the pressure of a gas also increases when volume and the amount of gas remain constant.

Basically, Temperature and Pressure are directly proportional.

Equation: \frac{P_{1}}{T_{1}} = \frac{P_{2} }{T_{2} }

Avogadro's Law: The most intuitive gas law. When you increase the amount of gas, the volume will also increase.

Meaning the moles (amount of gas) is directly proportional to volume.

Equation: \frac{V_{1} }{n_{1} } = \frac{V_{2} }{n_{2} } (n stands for moles)

There is a combined gas law and ideal gas law but those are just the gas laws mentioned above but combined together. These should be everything.

8 0
2 years ago
Read 2 more answers
15.35 L of gas is at a pressure of 198.0 kpa. At what pressure would the gas have a volume of 13.78
Ivahew [28]

Answer:

P₂ = 220.56KPa

Explanation:

Boyles Law P ∝ 1/V => Inverse relationship => Decreasing Volume => Increasing Pressure.

P₁ = 198 KPa           P₂ = ?

V₁ = 15.35 Liters     V₂ = 13.78 Liters

P₁V₁ = P₂V₂ => P₂ = P₁(V₁/V₂) = 198KPa(15.35 L/ 13.78L) = 220.6KPa

5 0
3 years ago
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