Answer:
Explanation:
is the magnetic quantum number.
The only possible value for the magnetic quantum number for an electron in an s orbital is 0.
The first three quantun numbers are:
- n: principal quantum number. It may have positive integer values: 1, 2, 3, 4,5, 6, 7, ...
: Azimuthal or angular momentum quantum number. It may have integer values from 0 to n - 1.
This quantum number is related to the type (or shape) of the orbital:
For s orbitals
For p orbitals
For d orbitals
For f orbitals
In this case, it is an s orbital, so we have
.
, the third quantum number can have integer values
to 
Since, for the s orbitals
, the only possible value for
is zero.
Answer:
Magnetic force, 
Explanation:
Given that,
A beryllium-9 ion has a positive charge that is double the charge of a proton, 
Speed of the ion in the magnetic field, 
Its velocity makes an angle of 61° with the direction of the magnetic field at the ion's location.
The magnitude of the field is 0.220 T.
We need to find the magnitude of the magnetic force on the ion. It is given by :

So, the magnitude of magnetic force on the ion is
.
Answer:
I don't know about these problems at all.
Explanation:
I don't know about physics at all
Answer:
Later high school years and freshman year of college
Explanation:
The transition from high school to college is an important developmental milestone that holds the potential for personal growth and behavioral change. A cohort of 2,025 students was recruited during the summer before they matriculated into college and completed Internet-based surveys about their participation in a variety of behavioral risks during the last three months of high school and throughout the first year of college. Alcohol use, marijuana use, and sex with multiple partners increased during the transition from high school to college, whereas driving after drinking, aggression, and property crimes decreased. Those from rural high schools and those who elected to live in private dormitories in college were at highest risk for heavy drinking and driving after drinking.
Answer:
2361.6N
Explanation:
Mass of player = 82kg
Velocity = 1.2m/s
Kinetic energy of player:
= 1/2mv²
= 1/2*82*1.2²
= 41x1.44
= 59.04J
Final kinetic energy = 0
Change in kinetic energy
|∆k| = |0-59.04|
= 59.04
Workdone by the feet = fd
d = 0.025
Fd = 59.04
F = 59.04/0.025
= 2361.6N
This is his average force.