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pav-90 [236]
3 years ago
9

A sound wave has a wavelength of 15 meters with a frequency of 2.5 Hz. What would the velocity be for this situation in

Physics
1 answer:
rodikova [14]3 years ago
7 0

Answer:

6m/s

Explanation:

V = frequency * wavelength

15 * 2.5 = 6m/s

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Complete the chart. All measurements are good to 1°C or better,
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3 years ago
An electron in a tv picture tube is accelerated through a potential difference of 10 kv before it hits the screen. What is the k
fomenos

Answer:

10,000 eV

Explanation:

Due to the law of conservation of energy, the kinetic energy of the electron at the end of its path is equal to its initial electric potential energy, given by:

U=q\Delta V

where

q is the electron charge

\Delta V is the potential difference

Here we have:

q=1 e is the electron's charged

\Delta V=10 kV=10,000 V is the potential difference

Substituting into the formula, we have

U=(1e)(10,000 V)=10,000 eV

8 0
4 years ago
Which of the following correctly describes the first animals that appeared?
Dvinal [7]
A these were large creatures similar to dinosaurs
7 0
4 years ago
A dentist using a dental drill brings it from rest to maximum operating speed of 382,000 rpm in 3.0 s. Assume that the drill acc
loris [4]

Answer:

a. \alpha =2122.22\: rev/s^{2}

b. \Delta \theta =9,550.02\: rev

Explanation:

The computation is shown below:

data provided in the question

The initial angular velocity  \small \omega o = 0 rev/s,

f = Final angular velocity = \small \omega = 382000 rpm i.e = \frac{382,000}{60} = 6,366.67

And time = t = 3.0s

Based on the above information

a. For angular acceleration of drill

\small \omega =\omega _{o}+\alpha t \\\\\ 6,366.67 = 0 + \alpha (3.0) \\\\ \alpha =2122.22\: rev/s^{2}

b. For the number of revolutions

\small \omega ^{2}-\omega _{o}^{2}=2\alpha \Delta \theta \\\\(6,366.67) ^{2}-(0)^{2}=2(2122.22) \Delta \theta \\\\ \Delta \theta =9,550.02\: rev

We simply applied the above formulas for determining each parts

3 0
3 years ago
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