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2 years ago

No one helped so im asking for these 2 again

Mathematics

1 answer:

ipn [44]2 years ago

3 0

Answer:

3. Option No. 2:

6x + 2y = 22

3x + 3y = 18

4. Option No. 2:

$2.50

Step by step explanation:

4. 6x + 2y = 22

(3x + 3y = 18) * 2

- Negate

6x + 2y = 22

6x + 6y = 36

2y - 6y = 22 - 36

-4y = -14

y = -14/-4

y = 3.5

An order of onion rings = $3.50

- Substitute to find for x

6x + 2(3.5) = 22

6x + 7 = 22

6x = 22 - 7

6x = 15

x = 15/6

x = 2.5

An order of French fries = $2.50

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Amiraneli [1.4K]

The side x is equal to 12

7 0

2 years ago

Find the exact value of the trigonometric function given that sinU=-7/25 and cosV=-4/5 (Both U and V are in Quadrant III)

Contact [7]

cosU:-

$\\ \rm\longmapsto \sqrt{1-sin^2U}=\sqrt{1-49/625}=24/25$

As U lies in Q3

cosU=-24/25

sinV

$\\ \rm\longmapsto \sqrt{1-cos^2V}=\sqrt{1-16/25}=3/4$

As V lies in Q3

sinV=-3/5

sin(V-U)=sinVcosU-cosVsinU=(-3/5)(-24/25)-(-4/5)(-7/25)=72/125-28/125=72-28/125=44/125
cos(U-V)=cosUcosV+sinUsinV=(-24/25)(-4/5)+(-7/25)(-3/5)=96/125+21/125=117/125

3 0

1 year ago

7. What is the volume of the prism? 8 cm 5.8 cm A. 29 cm B. 87 cm3 15.2 cm C. 512.3 cm3 D. 705.3 cm

bija089 [108]

The volume of the rectangular prism is

$V=L\times W\times H$

Where:

L is its length

W is its width

H is its height

From the given figure

L = 15.2 cm

W = 8 cm

H = 5.8 cm

Substitute them in the rule above

$\begin{gathered} V=15.2\times8\times5.8 \\ V=705.28\operatorname{cm}^3 \end{gathered}$

Round it to the nearest tenth

$V=705.3\operatorname{cm}^3$

Answer D

5 0

1 year ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

Answer:

3003 number of 5-member chess teams can be chosen from 15 interested players.

Step-by-step explanation:

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$