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Naya [18.7K]
3 years ago
10

If a 0.50 M solution of K2SO4 is slowly poured into a beaker containing 0.25 Mbarium nitrate and 0.30 M lead (II) nitrate at 25o

C, what will be the first precipitate that forms
Chemistry
1 answer:
postnew [5]3 years ago
6 0

Answer: The first precipitate formed is Barium Sulphate

Explanation:

This is because the reaction that takes place will be as follows:

K2SO4 + Ba (NO3)2 ------> BaSO4 + K2(NO3)2

And K2SO4 + Pb(NO3)2 -----> PbSO4 + K2(NO3)2

Considering the concentration of Barium Nitrate which is lower than that of Lead Nitrate it tends to attain equilibrium faster and the Barium salt or precipitate is formed....

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What impact would adding twice as much na2co3 than required for stoichiometric quantities have on the quantity of product produc
inn [45]

The product will not be affected by the addition of twice as much Na₂CO₃.

<h3>What is Limiting reagent in stoichiometry ?</h3>
  • The maximum quantity of the end product determined by a balanced chemical equation is known as the Stoichiometry.
  • The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced, and the one which remains unconsumed after the final reaction is in Excess.
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Here,taking the stoichiometry into consideration, we find that the reaction happens with 1:1 ratio; so, adding twice the amount of Na₂CO₃ will  lead to its excess making the other the limiting reactant, hence, it would not affect the yield of the product.

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What is the molar concentration (molarity) of a solution made by dissolving 0.285 moles of CaCl2(s) in just enough water to form
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Answer:

The answer to your question is Molarity = 0.238

Explanation:

Data

Molarity = ?

number of moles = 0.285

volume = 1.2 L

Molarity is a unit of concentration that relates the moles of a substance by the volume in liters.

Formula

Molarity = moles / volume

Substitution

Molarity = 0.285 / 1.2

Simplification and result

Molarity = 0.238

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3 years ago
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