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Naya [18.7K]
3 years ago
10

If a 0.50 M solution of K2SO4 is slowly poured into a beaker containing 0.25 Mbarium nitrate and 0.30 M lead (II) nitrate at 25o

C, what will be the first precipitate that forms
Chemistry
1 answer:
postnew [5]3 years ago
6 0

Answer: The first precipitate formed is Barium Sulphate

Explanation:

This is because the reaction that takes place will be as follows:

K2SO4 + Ba (NO3)2 ------> BaSO4 + K2(NO3)2

And K2SO4 + Pb(NO3)2 -----> PbSO4 + K2(NO3)2

Considering the concentration of Barium Nitrate which is lower than that of Lead Nitrate it tends to attain equilibrium faster and the Barium salt or precipitate is formed....

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Rank the ions in order of increasing basicity: CH3NH-, CH3CH2-, CH30-
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3 0
3 years ago
10. An atom that has 13 protons and 13 electrons is a neutral aluminum (Al) atom. An atom that has 13 protons and 10 electrons i
kotegsom [21]

Answer:

An atom of Al which has 13 protons and 10 electrons is Al cation (Al⁺³)

Explanation:

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Thus an atom of Al which has 13 protons and 10 electrons is Al cation (Al⁺³)

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4 years ago
Which one is you fav one
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Answer:

the 3rd one

Explanation:

8 0
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