2 years ago

F(x) - х3-14.х 16x 3х3 + 6x2_9x Чx

Mathematics

1 answer:

andrew-mc [135]2 years ago

8 0

Answer:

wrong❌❌

question

wrong❌❌

question

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3 years ago

Paul and Charlene are 420 miles apart. They start toward each other with Paul driving 16 mph faster than Charlene. They meet in

Thepotemich [5.8K]

Answer:

34 mph.

Step-by-step explanation:

Let x be speed of Charlene, then speed of Paul will be x+16 as we are given that Paul is driving 16 mph faster than Charlene.

Let y be distance covered by Charlene, then distance covered by Paul will be 420-y.

Now we will use formula $\text{Speed}=\frac{\text{Distance}}{\text{Time}}$ . Upon using our given information we will get two equation and two unknowns as:

$x+16=\frac{420-y}{5}...(1)$

$x=\frac{y}{5}...(2)$

Upon substituting $x=\frac{y}{5}$ in 1st equation we will get,

$\frac{y}{5}+16=\frac{420-y}{5}$

Upon multiplying both sides of our equation by 5 we will get,

$5(\frac{y}{5}+16)=420-y$

$5\times\frac{y}{5}+5\times 16=420-y$

$y+80=420-y$

$y+80+y=420-y+y$

$2y+80=420$

$2y=420-80$

$2y=340$

$y=\frac{340}{2}$

$y=170$

Upon substituting y=170 in 2nd equation we will get,

$x=\frac{170}{5}$

$x=34$

Therefore, Charlene's speed is 34 miles per hour.

6 0

3 years ago