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Assoli18 [71]
2 years ago
9

F(x) - х3-14.х 16x 3х3 + 6x2_9x Чx

Mathematics
1 answer:
andrew-mc [135]2 years ago
8 0

Answer:

wrong❌❌

question

wrong❌❌

question

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melamori03 [73]
The expression for the total amount that Lupita paid for the gown would be 1.06g.

The amount of the tax is 0.06g and the cost of the g is just 1g. If we add the two expressions together will will get the total amount paid.

0.06g + 1g = 1.06g
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3 years ago
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The first four terms of a sequence are shown below: 9, 5, 1, â’3 Which of the following functions best defines this sequence? f(
matrenka [14]

The function that best defines this arithmetic sequence is:

  • f(n) = f(n - 1) - 4, f(1) = 9

<h3>What is an arithmetic sequence?</h3>
  • In an <em>arithmetic sequence,</em> the <u>difference between consecutive terms is always the same</u>, called common difference d.

The recursive function that defines the sequence is:

f(n) = f(n - 1) + d

f(1) = f_0

  • In which f_0 is the first term.

In this problem, the sequence is: {9, 5, 1, -3}

  • Each term is the previous term subtracted by 4, hence d = -4.
  • The first term is 9, hence f_0 = 9.

Hence, the function is:

  • f(n) = f(n - 1) - 4, f(1) = 9

You can learn more about arithmetic sequences at brainly.com/question/6561461

5 0
2 years ago
Read 2 more answers
Simplify the expression:<br><br> 5(–5 + 3u) =
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Answer:

-25+15u

Step-by-step explanation:

all you need to do is distribute the 5 to everything in the parenthesis!

6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2%7D-1%7D%7B2-5a%7D%20times%20%5Cfrac%7B15a-6%7D%7Ba%5E%7B2%7D%2B5a-6%7D" id=
stepan [7]
\bf \cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\\\\&#10;-----------------------------\\\\&#10;recall\quad \textit{difference of squares}&#10;\\ \quad \\&#10;(a-b)(a+b) = a^2-b^2\qquad \qquad &#10;a^2-b^2 = (a-b)(a+b)\\\\&#10;thus\quad a^2-1\iff a^2-1^2\implies (a-1)(a+1)&#10;\\\\\\&#10;now\quad a^2+5a-6\implies (a+6)(a-1)\\\\&#10;-----------------------------\\\\&#10;thus&#10;\\\\\\&#10;\cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\implies \cfrac{(a-1)(a+1)}{2-5a}\times \cfrac{3(5a-2)}{(a+6)(a-1)}\\\\&#10;-----------------------------\\\\&#10;

\bf now\quad 3(5a-2) \iff -3(2-5a)\\\\&#10;-----------------------------\\\\&#10;thus&#10;\\\\\\&#10;\cfrac{\underline{(a-1)}(a+1)}{\underline{2-5a}}\times \cfrac{-3\underline{(2-5a)}}{(a+6)\underline{(a-1)}}\implies \cfrac{-3(a+1)}{a+6}
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3 years ago
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