First, we need to define k because it is a missing zero;
Knowing that a(2)=0;
a(t)=(t-k)(t-3)(t-6)(t+3)
a(2)=(2-k)(2-3)(2-6)(2+3)=0
(2-k)(-1)(-4)(5)=0
(2-k)(20)=0
(2-k)=0/20
2-k=0
2=k
Therefore, the final equation is a(t)=(t-2)(t-3)(3-6)(t+3) with the zeros being (2, 3, 6, -3)
Hope I helped :)

So, your answer to this problem is
x = <span>
±3√6i</span>
Answer:
+4
Step-by-step explanation:
Answer:
The Answer is 
Step-by-step explanation:
Let me draw this triangle for you as you haven't drawn the triangle.
To find the side SR , you have shown that
ΔPST ~(is similar to)ΔPRQ [AA]
As, you know when triangles are similar their sides are proportional.
So, 
You can solve this question using other way also
As, ST║RQ
then
⇒ [ if in a triangle a line is parallel to a side
intersecting the other two sides in distinct points then the ratio of the segments where the line segment intersects the other two sides are same.]

So you would do 5*2x +5*-8 +15=-15
Then simplify so it would be 10x + -40 + 15 = -15
Then add -40 and 15 together
Then it would be 10x + -25 = -15
Then add 25 to -25 and -15
So it would be 10x = 10
And then divide 10 from 10 with would be 1 so x = 1