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3 years ago

Where is the Oort cloud located

Chemistry

2 answers:

Karolina [17]3 years ago

5 0

To be honest I don’t even know

Vinil7 [7]3 years ago

4 0

Answer:

The Oort Cloud lies far beyond Pluto and the most distant edges of the Kuiper Belt. the Oort Cloud is believed to be a giant spherical shell surrounding the Sun, planets and Kuiper Belt Objects.

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Explain how the climate in a specific region differs during El Niño and La Niña. Please answer in your own words.

solmaris [256]

Answer:girl and boy

Explanation:

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4 years ago

How many milliliters of a 0.205 M solution of glucose, C6H12O6, are required to obtain 150.1 g of glucose?

jekas [21]

Answer:

4050 mL

Explanation:

Given data:

Mass of glucose = 150.1 g

Molarity of solution = 0.205 M

Volume of solution = ?

Solution:

Molarity = number of moles of solute / L of solution.

Now we will calculate the moles of sugar first.

Number of moles = mass/ molar mass

Number of moles = 150.1 g/ 180.156 g/mol

Number of moles = 0.83 mol

Now we will determine the volume:

Molarity = number of moles of solute / L of solution.

0.205 M = 0.83 mol / L of solution.

L of solution = 0.83 mol / 0.205 M

L of solution = 4.05 L

L to mL conversion:

4.05 L × 1000 mL / 1 L = 4050 mL

7 0

4 years ago

2KCIO3 ----------> 2KCI + 302 How many moles of KCIO3 are needed to make 3.5 moles of KCL?

lyudmila [28]

Answer:

3.5 mol KClO3

Explanation:

Given 3.50 moles of KCl as the target amount in the problem, used the coefficient of the balanced chemical reaction involved to determine the number of moles of potassium perchlorate needed.

x mole of KClO3 = 3.5 mol KCl x [(2 mol KCl)/ (2 mol KClO3)] = 3.5 mol KClO3

x mole of KClO3 = 3.5 mol KClO3

3 0

3 years ago

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is pro

sergeinik [125]

The question is incomplete, here is the complete question:

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water. If 12.5 g of water is produced from the reaction of 72.6 g of sulfuric acid and 77.0 g of sodium hydroxide, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.

Answer: The percent yield of water in the reaction is 46.85 %.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For NaOH:

Given mass of NaOH = 77.0 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

$\text{Moles of NaOH}=\frac{77.0g}{40g/mol}=1.925mol$

For sulfuric acid:

Given mass of sulfuric acid = 72.6 g

Molar mass of sulfuric acid = 98 g/mol

Putting values in equation 1, we get:

$\text{Moles of sulfuric acid}=\frac{72.6g}{98g/mol}=0.741mol$

The chemical equation for the reaction of NaOH and sulfuric acid follows:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of NaOH

So, 0.741 moles of sulfuric acid will react with = $\frac{2}{1}\times 0.741=1.482mol$ of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent.

Thus, sulfuric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of sulfuric acid produces 2 moles of water

So, 0.741 moles of sulfuric acid will produce = $\frac{2}{1}\times 0.741=1.482moles$ of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.482 moles

Putting values in equation 1, we get:

$1.482mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.482mol\times 18g/mol)=26.68g$

To calculate the percentage yield of water, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of water = 12.5 g

Theoretical yield of water = 26.68 g

Putting values in above equation, we get:

$\%\text{ yield of water}=\frac{12.5g}{26.68g}\times 100\\\\\% \text{yield of water}=46.85\%$

Hence, the percent yield of water in the reaction is 46.85 %.

8 0

3 years ago

The scientist finds fossilized remains of other species in the same rock layer as the trilobite. What can the scientist conclude

Sophie [7]

The Organisms that formed them likely lived during the Paleozoic era.

4 0

3 years ago

Where is the Oort cloud located​

Where is the Oort cloud located