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melisa1 [442]
1 year ago
12

What coefficients can be used to balance the following equation

Chemistry
1 answer:
zheka24 [161]1 year ago
5 0

The coefficient that can be used to balanced the given equation are 3, 2, 6, 1

<h3>What is a chemical equation? </h3>

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

<h3>How to balance the equation </h3>

K₂CO₃ + FeCl₃ -> KCl + Fe₂(CO₃)₃

There are 3 atoms of C on the right side and 1 on the left side. It can be balanced by writing 3 before K₂CO₃ as shown below:

3K₂CO₃ + FeCl₃ -> KCl + Fe₂(CO₃)₃

There are 6 atoms of K on the left side and 1 on the right side. it can be balanced by writing 6 before KCl as shown below:

3K₂CO₃ + FeCl₃ -> 6KCl + Fe₂(CO₃)₃

There are 6 atoms of Cl on the right side and 3 on the left. It can be balanced by writing 2 before FeCl₃ as shown below:

3K₂CO₃ + 2FeCl₃ -> 6KCl + Fe₂(CO₃)₃

Now the equation is balanced.

Thus, the coefficients are; 3, 2, 6, 1

Learn more about chemical equation:

brainly.com/question/7181548

#SPJ1

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3 years ago
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The molar mass of blood sugar, C6H12O6 also known as glucose and dextrose is
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The molar mass is calculated by looking up the relative atomic mass values on a periodic table. The relative atomic mass is a value without units that is calculated on a Carbon-12 scale.

By looking at the periodic table (values will be to 3 significant figures [<em>2</em><em> for hydrogen though]</em>):
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So the molar mass is essentially the relative atomic mass (RAM), but molar mass has a unit, but RAM doesn't (it is a ratio).

Given the formula is C6H12O6 (without putting the numbers as subscripts), we can calculate as follows:
M (C6H12O6) = (6 x 12.0) + (12 x 1.0) + (6 x 16.0)
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