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melisa1 [442]
1 year ago
12

What coefficients can be used to balance the following equation

Chemistry
1 answer:
zheka24 [161]1 year ago
5 0

The coefficient that can be used to balanced the given equation are 3, 2, 6, 1

<h3>What is a chemical equation? </h3>

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

<h3>How to balance the equation </h3>

K₂CO₃ + FeCl₃ -> KCl + Fe₂(CO₃)₃

There are 3 atoms of C on the right side and 1 on the left side. It can be balanced by writing 3 before K₂CO₃ as shown below:

3K₂CO₃ + FeCl₃ -> KCl + Fe₂(CO₃)₃

There are 6 atoms of K on the left side and 1 on the right side. it can be balanced by writing 6 before KCl as shown below:

3K₂CO₃ + FeCl₃ -> 6KCl + Fe₂(CO₃)₃

There are 6 atoms of Cl on the right side and 3 on the left. It can be balanced by writing 2 before FeCl₃ as shown below:

3K₂CO₃ + 2FeCl₃ -> 6KCl + Fe₂(CO₃)₃

Now the equation is balanced.

Thus, the coefficients are; 3, 2, 6, 1

Learn more about chemical equation:

brainly.com/question/7181548

#SPJ1

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Ionic bonds usually occur between metal and nonmetal ions. For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl.

Explanation:

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Calculate the wavelength of a red light with a frequency of 4.61 x 1012 Hz.
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The number of grams of H2 in 1470 mL of H2 gas. ​
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0.1313 g.

Explanation:

  • It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.
  • Suppose that hydrogen behaves ideally and at STP conditions.

<u><em>Using cross multiplication:</em></u>

1.0 mol of hydrogen occupies → 22.4 L.

??? mol of hydrogen occupies → 1.47 L.

∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.

  • Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:

<em>The no. of grams of hydrogen = no. of hydrogen moles x molar mass of hydrogen</em> = (6.563 x 10⁻² mol)(2.0 g/mol) = <em>0.1313 g.</em>

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