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mars1129 [50]
1 year ago
6

In the reaction shown below, what does the symbol "C" represent?

Biology
1 answer:
WARRIOR [948]1 year ago
8 0

The symbol C represents Carbon.

CaCO₃ ⇒ CaO + CO₂

Calcium carbonate is a compound which comprises of elements such as :

  • Calcium
  • Carbon
  • Oxygen

<h3>Compound</h3>

This is formed from the combination of two or more elements in a chemical

reaction. In this scenario, the  elements are combined in varying proportions

to form the compound.

Carbon is an elements which is denoted with the symbol C which makes it

the appropriate choice.

Read more about Compound here brainly.com/question/7849874

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A student is investigating cellular transport. She fills a beaker with 250 ml of water. She places 10 drops of red food coloring
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Answer:

The correct answer is A The student is investigating the passive transport of diffusion.

Explanation:

Diffusion is a type of transport process which helps in the transport of small molecules and gases towards their concentration gradient that"s means from region of high concentration to the low concentration region untill equilibrium is reached.

       In this question the 10 drops are red coloured food particles that are placed into the beaker, diffuses to all the regions of the beaker untill the concentration of that red colored food particle become same in all the regions to which red colored food particle diffuse.

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A new organism begins to form when egg and sperm cells join in the process called fertilization
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How many possible open reading frames (frames without stop codons) are there that extend through the following sequence? 5'... C
fenix001 [56]

Answer:

There are 4 reading frames without stop codons.

Explanation:

1) To find the possible reading frames you need to separate your sequence in codons (trios)  for the 5'-> 3' sense, first, excluding the first nucleotide, then excluding 2 nucleotides and then not excluding nucleotides.

5'... C TTA CAG TTT ATT GAT ACG GAG AAG G... 3'  NO STOP CODON

5'... CT TAC AGT TTA TTG ATA CGG AGA AGG... 3'  NO STOP CODON

5'... CTT ACA GTT TAT <u>TGA</u> TAC GGA GAA GG... 3'

2)Then you find the complementary sequence (which you already have)

3'... GAA TGT CAA ATA ACT ATG CCT CTT CC... 5'

3'... GA ATG TCA AAT AAC TAT GCC TCT TCC... 5'

3'... G AAT GTC AAA TAA CTA TGC CTC TTC C... 5'

3) Next, you have to obtain the reverse complementary

CCT TCT CCG TAT CAA TAA ACT GTA AG NO STOP CODON

CC TTC TCC GTA TCA ATA AAC TGT AAG NO STOP CODON

C CTT CTC CGT ATC AAT AAA CTG <u>TAA</u> G

4)Now you need to find start (AGT in terms of DNA) and stop codons(<u>TAA</u>, <u>TAG,</u> <u>TGA</u>, also in terms of DNA), in 5->3 and de reverse complementary.

<em />

<em>As you can see, you have for open reading frames that lack of stop codon, unfortunately, they also lack of AGT, the start codon.</em>

I added a table where you can find thestart and stop codons as well as the proteins that they translate to in terms of RNA.

I hope you find this information interesting and useful, good luck!

8 0
2 years ago
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