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Norma-Jean [14]
4 years ago
6

What is a difference between a law and a hypothesis?

Physics
1 answer:
AnnZ [28]4 years ago
8 0

The correct answer is

C ). A hypothesis includes an explanation for why two variables affect each other, but a law only describes how they affect each other.

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what gravitational force does the moon produce on the earth is their centers are 3.88x10(8)m apart and the moon has a mass of 7.
yawa3891 [41]

Isaac Newton compared the acceleration of the moon to the acceleration of objects on earth. Believing that gravitational forces were responsible for each, Newton was able to draw an important conclusion about the dependence of gravity upon distance. This comparison led him to conclude that the force of gravitational attraction between the Earth and other objects is inversely proportional to the distance separating the earth's center from the object's center. But distance is not the only variable affecting the magnitude of a gravitational force. Consider Newton's famous equation

Read more on Brainly.com - brainly.com/question/12278932#readmore

4 0
3 years ago
The net electric flux through a cubic box with sides that are 22.0 cm long is 4950 N⋅m2/C . What charge is enclosed by the box?
Bond [772]

Answer:

43.83 nC

Explanation:

We know Q = ε₀Ψ where Q = charge enclosed by the cubic box,  ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m and Ψ = net electric flux through cubic box = 4950 Nm²/C

So, substituting the values of the variables into the equation, we have

Q = ε₀Ψ

= 8.854 × 10⁻¹² F/m × 4950 Nm²/C

= 43827.3 × 10⁻¹² C = 4.38273 × 10⁻⁸ C

= 43.8273 × 10⁻⁹ C

= 43.8273 nC

≅ 43.83 nC

5 0
3 years ago
How do electromagnetic waves differ from mechanical waves?
stich3 [128]

They don't require a medium to propagate, meaning that they can travel through air, solid objects, and space.

6 0
4 years ago
If sugar contains 41.86% carbon and 6.98% hydrogen what percentage of sugar is oxygen?
MrMuchimi
If the only thing remaining is Oxygen then it is 51.16%.
4 0
4 years ago
Using the result of the preceding problem, (a) calculate the distance between fringes for 633-nm light falling on double slits s
vekshin1

To solve this problem it is necessary to apply the concepts related to the concept of superposition and the fringe separation for double slit experiment.

The equation can be written as

\Delta y = \frac{x\lambda}{d}

Where

\Delta y = Distance between fringes

x = distance between slits and screen

d = Distance between slits

\lambda= Wavelength

Our values are given as

d= 0.08mm

x =3m

\lambda = 633nm

In this way replacing in the equation,

\Delta y = \frac{x\lambda}{d}

\Delta y = \frac{3m(633nm*(\frac{1*10^{-9}}{1nm}))}{0.08*(\frac{1*10^{-3}m}{1mm})}

\Delta y = 2.37*10^{-2}m

\Delta y = 2.37cm

Therefore the distance between the fringes is 2.37cm

PART B) For the case in which it is submerged in water it is necessary to apply the relationship of the fringes with the index of refraction therefore

\Delta Y_2 = \frac{\Delta Y_1}{n}

\Delta Y_2 = \frac{2.37}{1.33}

\Delta Y_2 = 1.78cm

3 0
4 years ago
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