Answer:
2.4 meters
Explanation:
Let
m1= 10 kg
m2= 6 kg
Distance of m2 from pivot = 4 m
Distance of m1 from pivot = x (suppose) =?
If system is not rotating then it should be in equilibrrium position. And in this case clock-wise and anti -clock wise torques should balance each other i-e
weight of m1 mass bolck × x = weight of m2 mass block × 4
m1×g× x = m2 × g × 4
==> 10×9.8×x= 6×9.8×4
==> x = 6×9.8×4 / 10×9.8
==> x = 24/10=2.4 m
Answer:
for a mass m = 10kg on Earth it`s weight is W = mg = 10 x 10 = 100N.
Explanation:
The electric force between two charges is:
F = (9 x 10⁹) Q₁ Q₂ / D²
F is the force, in Newtons
Q₁ and Q₂ are the two charges, in Coulombs
D is the distance between them, in meters
I'm going to assume that the first little 'c' in the question stands for "Coulombs", and the second little 'c' stands for "centimeters". And now, I'll proceed to answer the question that I've just invented.
For these two electrons:
F = (9 x 10⁹) (1.6 x 10⁻¹⁹) (1.6 x 10⁻¹⁹) / (5.4 x 10⁻⁷)²
F = (9 x 1.6 x 1.6 x 10⁻²⁹) / (5.4² x 10⁻¹⁴)
F = (23.04 / 29.16) x 10⁻¹⁵
<em>F = 7.9 x 10⁻¹⁶ of a Newton</em>
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EACH electron feels that same force, pushing it away from the other electron.
PE = mgh
where
m = mass
g = acceleration due to gravity
h = height