Answer:
6.7 * (10^7) = 67 000 000
So first you want to convert both to have the same denominator.
5 1/2 - 3 3/4
To:
5 2/4 - 3 3/4
Now, to make it easier for me, I would convert both to an improper fraction.
5 2/4 -> 22/4
3 3/4 -> 15/4
So now you can just do,
22/4 - 15/4,
which is just 7/4.
This in mixed number form is 1 3/4.
Answer:
<em>There are approximately 114 rabbits in the year 10</em>
Step-by-step explanation:
<u>Exponential Growth
</u>
The natural growth of some magnitudes can be modeled by the equation:

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.
We are given two measurements of the population of rabbits on an island.
In year 1, there are 50 rabbits. This is the point (1,50)
In year 5, there are 72 rabbits. This is the point (5,72)
Substituting in the general model, we have:

![50=P_o(1+r)\qquad\qquad[1]](https://tex.z-dn.net/?f=50%3DP_o%281%2Br%29%5Cqquad%5Cqquad%5B1%5D)
![72=P_o(1+r)^5\qquad\qquad[2]](https://tex.z-dn.net/?f=72%3DP_o%281%2Br%29%5E5%5Cqquad%5Cqquad%5B2%5D)
Dividing [2] by [1]:

Solving for r:
![\displaystyle r=\sqrt[4]{\frac{72}{50}}-1](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B72%7D%7B50%7D%7D-1)
Calculating:
r=0.095445
From [1], solve for Po:



The model can be written now as:

In year t=10, the population of rabbits is:

P = 113.6

There are approximately 114 rabbits in the year 10
Answer:
he age of girl 3
years ago is 8.5 years .
Step-by-step explanation:
Given as :
The present age of seventh grader girl = 12 years
Let The age of her 3
years ago = x years
So The age of girl
years ago = x years
<u>Now, According to question</u>
The age of girl 3.5 years ago = 12 - 3.5
Or, The age of girl 3.5 years ago = 8.5 years
Hence The age of girl 3
years ago is 8.5 years . Answer